Geo_Book_Answers
Geo_Book_Answers
Geo_Book_Answers
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LESSON 13.5<br />
1. D: Paris is in France; Tucson is in the U.S.;<br />
London is in England. Bamako must be the capital<br />
of Mali.<br />
2. C: The “Sir” in part A shows that Halley was<br />
English; Julius Caesar was an emperor, not a<br />
scientist; Madonna is a singer. Galileo Galilei must<br />
be the answer.<br />
3. No, the proof is claiming only that if two<br />
particular angles are not congruent, then the two<br />
particular sides opposite them are not congruent. It<br />
still might be the case that a different pair of angles<br />
are congruent and that therefore a different pair of<br />
sides are congruent.<br />
4. Yes, this statement is the contrapositive of the<br />
conjecture proved in Example B, so they are<br />
logically equivalent.<br />
5. 1. Assume the opposite of the conclusion;<br />
2. Triangle Sum Theorem; 3. Substitution property<br />
of equality; 4. 0°; Subtraction property of equality<br />
6. Assume ZOID is equiangular. Use the definition<br />
of equiangular and the Four Congruent Angles<br />
Rectangle Theorem to prove that ZOID is a<br />
rectangle. Therefore ZOID is a parallelogram, which<br />
creates a contradiction.<br />
7. Assume CD is the altitude to AB. Use the<br />
definitions of altitude, median, and midpoint, the<br />
Right Angles Are Congruent Theorem, and the<br />
SAS Congruence Postulate to get ADC BDC.<br />
Therefore AC BC, which creates a contradiction.<br />
8. Assume ZO ID. Use the Opposite Sides<br />
Parallel and Congruent Theorem to prove that<br />
ZOID is a parallelogram, which creates a<br />
contradiction.<br />
9. Given: Circle O with chord AB and perpendicular<br />
bisector CD <br />
Show: CD passes through O<br />
Assume CD does not pass through O. Use the Line<br />
Postulate to construct OB and OA and the<br />
Perpendicular Postulate to construct OE. Then use<br />
the Isosceles Triangle Theorem, the Right Angles<br />
Are Congruent Theorem, and the SAA Theorem to<br />
get OEA OEB. From CPCTC and the<br />
definition of midpoint, prove that E is the midpoint<br />
of AB, which creates a contradiction.<br />
C<br />
O<br />
10. a 75°, b 47°, c 58°<br />
11. 42 ft3 132 ft 3<br />
12a.<br />
12b. 1 3 <br />
13a. A<br />
13b. N<br />
13c. S<br />
13d. S<br />
13e. A<br />
<br />
3 <br />
3<br />
<br />
4 12<br />
B<br />
D<br />
E<br />
A<br />
ANSWERS TO EXERCISES 151<br />
<strong>Answers</strong> to Exercises