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LESSON 13.5<br />

1. D: Paris is in France; Tucson is in the U.S.;<br />

London is in England. Bamako must be the capital<br />

of Mali.<br />

2. C: The “Sir” in part A shows that Halley was<br />

English; Julius Caesar was an emperor, not a<br />

scientist; Madonna is a singer. Galileo Galilei must<br />

be the answer.<br />

3. No, the proof is claiming only that if two<br />

particular angles are not congruent, then the two<br />

particular sides opposite them are not congruent. It<br />

still might be the case that a different pair of angles<br />

are congruent and that therefore a different pair of<br />

sides are congruent.<br />

4. Yes, this statement is the contrapositive of the<br />

conjecture proved in Example B, so they are<br />

logically equivalent.<br />

5. 1. Assume the opposite of the conclusion;<br />

2. Triangle Sum Theorem; 3. Substitution property<br />

of equality; 4. 0°; Subtraction property of equality<br />

6. Assume ZOID is equiangular. Use the definition<br />

of equiangular and the Four Congruent Angles<br />

Rectangle Theorem to prove that ZOID is a<br />

rectangle. Therefore ZOID is a parallelogram, which<br />

creates a contradiction.<br />

7. Assume CD is the altitude to AB. Use the<br />

definitions of altitude, median, and midpoint, the<br />

Right Angles Are Congruent Theorem, and the<br />

SAS Congruence Postulate to get ADC BDC.<br />

Therefore AC BC, which creates a contradiction.<br />

8. Assume ZO ID. Use the Opposite Sides<br />

Parallel and Congruent Theorem to prove that<br />

ZOID is a parallelogram, which creates a<br />

contradiction.<br />

9. Given: Circle O with chord AB and perpendicular<br />

bisector CD <br />

Show: CD passes through O<br />

Assume CD does not pass through O. Use the Line<br />

Postulate to construct OB and OA and the<br />

Perpendicular Postulate to construct OE. Then use<br />

the Isosceles Triangle Theorem, the Right Angles<br />

Are Congruent Theorem, and the SAA Theorem to<br />

get OEA OEB. From CPCTC and the<br />

definition of midpoint, prove that E is the midpoint<br />

of AB, which creates a contradiction.<br />

C<br />

O<br />

10. a 75°, b 47°, c 58°<br />

11. 42 ft3 132 ft 3<br />

12a.<br />

12b. 1 3 <br />

13a. A<br />

13b. N<br />

13c. S<br />

13d. S<br />

13e. A<br />

<br />

3 <br />

3<br />

<br />

4 12<br />

B<br />

D<br />

E<br />

A<br />

ANSWERS TO EXERCISES 151<br />

<strong>Answers</strong> to Exercises

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