Geo_Book_Answers
Geo_Book_Answers
Geo_Book_Answers
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<strong>Answers</strong> to Exercises<br />
11.<br />
A<br />
2 1<br />
D<br />
4<br />
3<br />
Use the Parallelogram Opposite Angles Theorem,<br />
the multiplication property, and the definition of<br />
angle bisector to get 1 3. Then use the<br />
Converse of the Isosceles Triangle Theorem,<br />
the definition of isosceles triangle, and the<br />
Parallelogram Opposite Sides Theorem to get<br />
AB BC DC AD .<br />
12.<br />
W Z<br />
X P Y<br />
Use the Converse of the Angle Bisector Theorem<br />
to prove that WY is the angle bisector of Y. In<br />
like manner, WY is the angle bisector of W.<br />
Therefore, WXYZ is a rhombus by the Converse<br />
of the Rhombus Angles Theorem.<br />
13. Linear Pair Postulate<br />
CA Postulate<br />
Interior Supplements Theorem<br />
Parallelogram Consec. Angle Theorem<br />
150 ANSWERS TO EXERCISES<br />
B<br />
C<br />
Q<br />
17. (Lesson 13.4)<br />
parallelogram<br />
2 diagonals<br />
2 bisectors<br />
of sides<br />
isosceles<br />
trapezoid<br />
14.<br />
ASA Congruence<br />
Postulate<br />
Parallelogram<br />
Diagonal Lemma<br />
Opposite Sides<br />
Theorem<br />
Converse of the<br />
IT Theorem<br />
Opposite Angles<br />
Theorem<br />
Converse of the Rhombus<br />
Angles Theorem<br />
Line Postulate Angle Addition<br />
Postulate<br />
Double-Edged<br />
Straightedge Theorem<br />
SSS Congruence<br />
Postulate<br />
IT Theorem<br />
Converse of the Angle<br />
Bisector Theorem<br />
15a. A<br />
15b. S<br />
15c. S<br />
15d. N<br />
16. 2386 ft 2<br />
17. See table below.<br />
18. V 1 V 2 has length 12.8 and bearing 72.6°.<br />
19a. B<br />
19b. A<br />
20a. 19°<br />
20b. 52°<br />
20c. 52°<br />
20d. 232°<br />
20e. 19°<br />
Name Lines of symmetry Rotational symmetry<br />
none 2-fold<br />
trapezoid none none<br />
kite 1 diagonal none<br />
square 4-fold<br />
rectangle 2 bisectors of sides 2-fold<br />
rhombus 2 diagonals 2-fold<br />
1 bisector of sides none