Geo_Book_Answers
Geo_Book_Answers
Geo_Book_Answers
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LESSON 13.3<br />
1. Case 1: P is collinear with A and B. Use the Line<br />
Intersection Postulate to show that P and E are the<br />
same point and use the definitions of bisector and<br />
midpoint to get AP BP.<br />
Case 2: P is not collinear with A<br />
and B. Use the SAS Congruence Postulate to get<br />
AEP BEP. Then use CPCTC to get AP BP.<br />
A<br />
2. Case 1: P is collinear with A and B. Use the<br />
definitions of congruence and midpoint to show<br />
that P is the midpoint of AB.Then use the<br />
definition of perpendicular bisector.<br />
A<br />
C<br />
P<br />
E<br />
D<br />
P<br />
E<br />
Case 2: P is not collinear with A and B.Draw<br />
midpoint E and PE. Use the SSS Congruence<br />
Postulate to get AEP BEP. Then use CPCTC<br />
and the Congruent and Supplementary Theorem<br />
to prove that AEP and BEP are both right<br />
angles. Therefore PE is the perpendicular bisector<br />
of AB by the definitions of midpoint and<br />
perpendicular.<br />
3. Use the reflexive property and<br />
C<br />
the SSS Congruence Postulate to get<br />
ABC BAC. Therefore,<br />
A B by CPCTC.<br />
4. Use the reflexive property and<br />
the ASA Congruence Postulate to<br />
get ABC BAC. Then use<br />
CPCTC and the definition of<br />
isosceles triangle.<br />
5.<br />
B<br />
C A<br />
P<br />
B<br />
B<br />
A B<br />
A B<br />
Draw line BA.<br />
Use the Isosceles Triangle Theorem to get<br />
PAB PBA. Use the Angle Addition<br />
Postulate and the subtraction property to get<br />
BAC ABC. Then use the Converse of the<br />
C<br />
Isosceles Triangle Theorem (CB CA), the reflexive<br />
property, and the SSS Congruence Postulate to get<br />
ACP BCP. Therefore,ACP BCP by<br />
CPCTC.<br />
6.<br />
C m<br />
A<br />
Use the Line Intersection Postulate and the<br />
Perpendicular Bisector Theorem to get AP BP<br />
and BP CP. Then use the transitive property and<br />
the Converse of the Perpendicular Bisector<br />
Theorem to prove that point P is on line n.<br />
7.<br />
C<br />
Use the Line Intersection Postulate and the Angle<br />
Bisector Theorem to prove that Q is equally distant<br />
from AB and AC and from AB and BC. Then use the<br />
transitive property and the Converse of the Angle<br />
Bisector Theorem to prove that point Q is on line n.<br />
8.<br />
B<br />
A<br />
Use the Linear Pair Postulate and the definition of<br />
supplementary angles to get m3 m4 180°.<br />
Then use the Triangle Sum Theorem and the<br />
transitive property to get m1 m2 <br />
m3 m3 m4. Therefore, m1 <br />
m2 m4 by the subtraction property.<br />
9. D<br />
A<br />
n<br />
m<br />
A B<br />
1<br />
3 4<br />
2<br />
1<br />
2<br />
B<br />
Q<br />
n<br />
P<br />
<br />
3 4<br />
C<br />
C<br />
<br />
Use the Triangle Sum Theorem and the addition<br />
property to get mA m1 m3 mC <br />
m4 m2 360°. Then use the Angle Addition<br />
Postulate and the substitution property to get<br />
mA mABC mC mCDA 360°.<br />
10. Use the definitions of median<br />
and midpoint to get BM 1 BC 2 and<br />
AN 1<br />
C<br />
N M<br />
AC. 2 Then use the multiplication<br />
property and the substitution<br />
A B<br />
property to get AN BM . By the<br />
reflexive property, the Isosceles Triangle Theorem,<br />
and the SAS Congruence Postulate, ABN <br />
BAM. Therefore, BN AM by CPCTC.<br />
B<br />
ANSWERS TO EXERCISES 147<br />
<strong>Answers</strong> to Exercises