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Geo_Book_Answers

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<strong>Answers</strong> to Exercises<br />

LESSON 11.7<br />

1. 5 cm 2. 33 1<br />

<br />

3<br />

cm<br />

3. 45 cm 4. 21 cm<br />

5. 28 cm 6. no<br />

7. José’s method is correct. Possible explanation:<br />

Alex’s first ratio compares only part of a side of the<br />

larger triangle to the entire corresponding side of the<br />

smaller triangle, while the second ratio compares<br />

entire corresponding sides of the triangles.<br />

8. yes<br />

9. 6 cm; 4.5 cm<br />

10. 13.3 cm; 21.6 cm<br />

11. yes; no; no<br />

12. yes; yes; yes<br />

13. 32 cm; 62 cm<br />

14.<br />

15.<br />

E<br />

16. Extended Parallel/Proportionality Conjecture<br />

17. You should connect the two 75-marks. By the<br />

Extended Parallel/Proportionality Conjecture,<br />

drawing a segment between the 75-marks will<br />

75<br />

form a similar segment that has length <br />

100<br />

of the original.<br />

18. 2064 cm3 6484 cm3 19. possible proof:<br />

a b<br />

<br />

c d<br />

I J<br />

ad cb<br />

ad ab cb ab<br />

a(d b) b(c a)<br />

a(d b)<br />

<br />

ab<br />

b(c a)<br />

<br />

ab<br />

d b c a<br />

b<br />

a<br />

132 ANSWERS TO EXERCISES<br />

F<br />

, or 75%,<br />

So two pairs of corresponding sides of XYZ and<br />

XAB are proportional. X X, so<br />

XYZ XAB by the SAS Similarity Conjecture.<br />

Because XYZ XAB, XAB XYZ.<br />

Hence, AB YZ by the Converse of the Parallel<br />

Lines Conjecture.<br />

20. Set the screw so that the shorter lengths of the<br />

styluses are three-fourths as long as the longer<br />

lengths.<br />

21. x 4.6 cm, y 3.4 cm<br />

22. x 45 ft, y 40 ft, z 35 ft<br />

23. 343<br />

<br />

729<br />

24. She is incorrect. She can make only nine 8 cm<br />

diameter spheres.<br />

25. 6x2 ;24x2 ;54x2 26. 1<br />

3 r<br />

27a. Possible construction method: Use the<br />

triangle-and-circle construction from Lesson 11.3,<br />

Exercise 18, to locate the golden cut, X, of AB.<br />

Then use perpendicular lines and circles to create a<br />

rectangle with length AB and width AX.<br />

27b. Possible construction method: Construct<br />

golden rectangle ABCD following the method from<br />

27a. For square AEFD, locate EF by constructing<br />

circle A and circle D each with radius AD. Repeat<br />

the process of cutting off squares as often as<br />

desired. For the golden spiral from point D to point<br />

E, construct circle F with radius EF; select point D,<br />

point E, and circle F and choose Arc On Circle from<br />

the Construct menu.<br />

28. possible answer:<br />

A<br />

S<br />

P<br />

D<br />

B<br />

R<br />

Q<br />

C<br />

Given: Circumscribed quadrilateral ABCD, with<br />

points of tangency P, Q , R, and S<br />

Show: AB DC AD BC

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