Geo_Book_Answers
Geo_Book_Answers
Geo_Book_Answers
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<strong>Answers</strong> to Exercises<br />
LESSON 11.7<br />
1. 5 cm 2. 33 1<br />
<br />
3<br />
cm<br />
3. 45 cm 4. 21 cm<br />
5. 28 cm 6. no<br />
7. José’s method is correct. Possible explanation:<br />
Alex’s first ratio compares only part of a side of the<br />
larger triangle to the entire corresponding side of the<br />
smaller triangle, while the second ratio compares<br />
entire corresponding sides of the triangles.<br />
8. yes<br />
9. 6 cm; 4.5 cm<br />
10. 13.3 cm; 21.6 cm<br />
11. yes; no; no<br />
12. yes; yes; yes<br />
13. 32 cm; 62 cm<br />
14.<br />
15.<br />
E<br />
16. Extended Parallel/Proportionality Conjecture<br />
17. You should connect the two 75-marks. By the<br />
Extended Parallel/Proportionality Conjecture,<br />
drawing a segment between the 75-marks will<br />
75<br />
form a similar segment that has length <br />
100<br />
of the original.<br />
18. 2064 cm3 6484 cm3 19. possible proof:<br />
a b<br />
<br />
c d<br />
I J<br />
ad cb<br />
ad ab cb ab<br />
a(d b) b(c a)<br />
a(d b)<br />
<br />
ab<br />
b(c a)<br />
<br />
ab<br />
d b c a<br />
b<br />
a<br />
132 ANSWERS TO EXERCISES<br />
F<br />
, or 75%,<br />
So two pairs of corresponding sides of XYZ and<br />
XAB are proportional. X X, so<br />
XYZ XAB by the SAS Similarity Conjecture.<br />
Because XYZ XAB, XAB XYZ.<br />
Hence, AB YZ by the Converse of the Parallel<br />
Lines Conjecture.<br />
20. Set the screw so that the shorter lengths of the<br />
styluses are three-fourths as long as the longer<br />
lengths.<br />
21. x 4.6 cm, y 3.4 cm<br />
22. x 45 ft, y 40 ft, z 35 ft<br />
23. 343<br />
<br />
729<br />
24. She is incorrect. She can make only nine 8 cm<br />
diameter spheres.<br />
25. 6x2 ;24x2 ;54x2 26. 1<br />
3 r<br />
27a. Possible construction method: Use the<br />
triangle-and-circle construction from Lesson 11.3,<br />
Exercise 18, to locate the golden cut, X, of AB.<br />
Then use perpendicular lines and circles to create a<br />
rectangle with length AB and width AX.<br />
27b. Possible construction method: Construct<br />
golden rectangle ABCD following the method from<br />
27a. For square AEFD, locate EF by constructing<br />
circle A and circle D each with radius AD. Repeat<br />
the process of cutting off squares as often as<br />
desired. For the golden spiral from point D to point<br />
E, construct circle F with radius EF; select point D,<br />
point E, and circle F and choose Arc On Circle from<br />
the Construct menu.<br />
28. possible answer:<br />
A<br />
S<br />
P<br />
D<br />
B<br />
R<br />
Q<br />
C<br />
Given: Circumscribed quadrilateral ABCD, with<br />
points of tangency P, Q , R, and S<br />
Show: AB DC AD BC