Issue 17 - Free-Energy Devices

is not charge motion
with respect to the existing electric field, the
energy produced could be due to the
gravitational space time energy absorbed
through a gravitational matter space time field
created due to the existing electric field; the
thrust could be due to gravitational space time
absorbed momentum change; such a
moving system is the system under study.
2. Proposed Asymmetric Capacitors System
2.1 General
Inside a dielectric means 1 (Fig. 1) are placed
metallic conductors 3 which are electrically
charged in relation to the metallic casing 2,
which is electrically neutral.
Fig.1
Zero potential casing asymmetric capacitor system . General
arrangement
This is achieved by means of high voltage
imposed between the conductors 3 and the
metallic casing 2. We assume that the
electrostatic field equation is everywhere in
force, which concerning isotropic materials
with constant specific inductive capacity
(dielectric constant) is as follows:
(1)
where E r is the field intensity, φ –the
potential, ρ − the density of spatial charge.
The force F according to equation (1) for an
area enclosed by a surface S is[13]:
(2)
where D is the electric displacement and n
the orthogonal unitary vector on the surface S
directed outside the area enclosed by the
surface S . Consequently the resultant force
tot F on the whole system, according to
equation (2) will be:
74 New Energy Technologies, Issue #3(18) 2004
(3)
where ds is an elementary surface unit and dq
the surface charge corresponding to the
surface dS.
The force F tot is equal to zero because the field
intensity E on the outer surface of the casing 2
is equal to zero. In reality a charge dq on a
metallic surface creates by induction a charge q
d on the dielectric 1 surface so that:
(4)
where ε r is the relative dielectric constant of
the dielectric means 1 [14,15].
Due to the equation (4), the total resulting force
F, exerted on the charges dq and (-dq’) , because
of the existing electric field of intensity E
corresponding to a surface element on the
surfaces 2 in or 3 out , will be:
(5)
A coefficient 1/2 is needed because of dq and
(dq’), distribution[16]; Eq.(5) shows that at the
system surfaces always an acting force exists.
Because of Eq.(5) we have:
(6)
wherein F M is the total resultant force exerted
on the conductors 2, 3, being derived if we
assume thatequation (2) is in force. Then tot F,
according to equation (3) should be equal to
zero. When however the total resultant force
F M exerted on the metallic elements 2,3 is not
equal to zero, then, according to
equation (6), F tot will not be equal to zero as