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Differential Calculus-I - New Age International

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DIFFERENTIAL CALCULUS-I 7<br />

dy<br />

y 1 =<br />

dx<br />

2<br />

= ( m loga)<br />

⋅ y<br />

d y<br />

y 2 = = m loga ⋅ y<br />

2<br />

1<br />

dx<br />

= ( m loga)(<br />

m loga)<br />

⋅ y<br />

3<br />

= ( mloga)<br />

d y<br />

2<br />

y 3 = = ( mlog a) ⋅y<br />

3<br />

dx<br />

= ( mloga)<br />

2<br />

3<br />

y<br />

y<br />

........................<br />

........................<br />

n<br />

d y<br />

y n = n<br />

m a y<br />

n = ( log ) ⋅<br />

dx<br />

n mx<br />

[ ]<br />

D a = ( mlog a) ⋅a<br />

1<br />

n mx<br />

WORKED EXAMPLES<br />

Example Example 1: 1: Find the nth derivative of the following functions:<br />

Solution:<br />

Solution:<br />

(i) 3<br />

y = sin x<br />

(i) sin 3 x (ii) cos 4 x.<br />

where 3<br />

x<br />

\ (sin )<br />

3 D x<br />

n<br />

(ii) y = cos 4 x<br />

where 2<br />

x<br />

so that 4<br />

cos x<br />

1<br />

sin = ( 3sin<br />

x − sin3x)<br />

4<br />

3 n 1 n<br />

= D (sinx)<br />

− D (sin3x)<br />

4 4<br />

=<br />

3 ⎛ nπ<br />

⎞ 3 ⎛ nπ<br />

⎞<br />

sin⎜<br />

x + ⎟ − sin⎜3x<br />

+ ⎟<br />

4 ⎝ 2 ⎠ 4 ⎝ 2 ⎠<br />

1<br />

cos = ( 1 + cos2x)<br />

2<br />

1<br />

= ( 1+<br />

cos2x)<br />

4<br />

1 2<br />

=<br />

[ 1+<br />

cos 2x<br />

+ 2cos2x]<br />

4<br />

2<br />

n<br />

[Using the formula (15)]

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