Differential Calculus-I - New Age International
Differential Calculus-I - New Age International
Differential Calculus-I - New Age International
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DIFFERENTIAL CALCULUS-I 7<br />
dy<br />
y 1 =<br />
dx<br />
2<br />
= ( m loga)<br />
⋅ y<br />
d y<br />
y 2 = = m loga ⋅ y<br />
2<br />
1<br />
dx<br />
= ( m loga)(<br />
m loga)<br />
⋅ y<br />
3<br />
= ( mloga)<br />
d y<br />
2<br />
y 3 = = ( mlog a) ⋅y<br />
3<br />
dx<br />
= ( mloga)<br />
2<br />
3<br />
y<br />
y<br />
........................<br />
........................<br />
n<br />
d y<br />
y n = n<br />
m a y<br />
n = ( log ) ⋅<br />
dx<br />
n mx<br />
[ ]<br />
D a = ( mlog a) ⋅a<br />
1<br />
n mx<br />
WORKED EXAMPLES<br />
Example Example 1: 1: Find the nth derivative of the following functions:<br />
Solution:<br />
Solution:<br />
(i) 3<br />
y = sin x<br />
(i) sin 3 x (ii) cos 4 x.<br />
where 3<br />
x<br />
\ (sin )<br />
3 D x<br />
n<br />
(ii) y = cos 4 x<br />
where 2<br />
x<br />
so that 4<br />
cos x<br />
1<br />
sin = ( 3sin<br />
x − sin3x)<br />
4<br />
3 n 1 n<br />
= D (sinx)<br />
− D (sin3x)<br />
4 4<br />
=<br />
3 ⎛ nπ<br />
⎞ 3 ⎛ nπ<br />
⎞<br />
sin⎜<br />
x + ⎟ − sin⎜3x<br />
+ ⎟<br />
4 ⎝ 2 ⎠ 4 ⎝ 2 ⎠<br />
1<br />
cos = ( 1 + cos2x)<br />
2<br />
1<br />
= ( 1+<br />
cos2x)<br />
4<br />
1 2<br />
=<br />
[ 1+<br />
cos 2x<br />
+ 2cos2x]<br />
4<br />
2<br />
n<br />
[Using the formula (15)]