How Large Is One Zillion? - Diwa Learning Systems

How Large Is One Zillion? - Diwa Learning Systems How Large Is One Zillion? - Diwa Learning Systems

03.04.2013 Views

Answers to Exercises How Large Is One Zillion? Exercise 1 A. Factoring xm xn = xm–n , x ≠ 0 Addition of Integers x –n = 1 xn , x ≠ 0 ( x y ) n = xn y n (xm ) n = xmn Expanding the power B. Expressing numbers in terms of exponents Exercise 2 (xm ) n = xmn and x0 = 1, x ≠ 0 x m · x n = x m+n Addition of integers x –n = 1 x n , x ≠ 0 and x 0 = 1, x ≠ 0 1 2 3 4 5 0 1 6 8 9 4 6 7 . 3 2 . 8 1 8 9 10 0 2 0 2 4 0 12 11 0 4 4 8 0 0 1 4 4 0 13 14 0 1 1 3 0 15 16 17 0 8 1 2 0 0 18 19 20 4 3 . 3 0 0 21 22 1 0 6 4 4 0 Factor In Answer to the Preliminary Problem: 0, one of the factors is (x – x) = 0 TATSULOK Second Year Vol. 11 No. 3 e-Pages I. 1. Factor = 3ab (a2 – 3ab + 9b) 2 2. Factor = (m – n)(3m – 1) 3. Factor = 4(u – 1)(2 – v) II. (1) To factor x2 + 5x + 6, I need two numbers that add up to 5 and have a product of 6. Thus, x2 + 5x + 6 = (x + 5)(x + 1). (2) To factor x2 – 2x – 3, I need two numbers that add up to –2 and have a product of –3. Thus, x2 – 2x – 3 = (x – 3)(x + 1). (3) To factor x2 – 8x + 15, I need two numbers that add up to –8 and have a product of 15. Thus, x2 – 8x + 15 = (x – 3)(x – 5). III. 1. (x + 7) and (x + 4) 2. (x + 3) 2 3. (x + 4) and (x – 1) 4. (4x – 1) and (3x – 4) 5. a b c d 8

Answers to Exercises<br />

<strong>How</strong> <strong>Large</strong> <strong>Is</strong> <strong>One</strong> <strong>Zillion</strong>?<br />

Exercise 1<br />

A. Factoring<br />

xm xn = xm–n , x ≠ 0<br />

Addition of Integers<br />

x –n = 1<br />

xn , x ≠ 0<br />

( x<br />

y ) n<br />

= xn<br />

y n<br />

(xm ) n<br />

= xmn Expanding the power<br />

B. Expressing numbers in terms of<br />

exponents<br />

Exercise 2<br />

(xm ) n<br />

= xmn and x0 = 1, x ≠ 0<br />

x m · x n = x m+n<br />

Addition of integers<br />

x –n = 1<br />

x n , x ≠ 0 and x 0 = 1, x ≠ 0<br />

1 2 3 4 5<br />

0 1 6 8 9 4<br />

6 7<br />

. 3 2 . 8 1<br />

8 9 10<br />

0 2 0 2 4 0<br />

12<br />

11<br />

0 4 4 8 0<br />

0 1 4 4 0<br />

13 14<br />

0 1 1 3 0<br />

15 16 17<br />

0 8 1 2 0 0<br />

18 19 20<br />

4 3 . 3 0 0<br />

21 22<br />

1 0 6 4 4 0<br />

Factor In<br />

Answer to the Preliminary Problem:<br />

0, one of the factors is (x – x) = 0<br />

TATSULOK Second Year Vol. 11 No. 3 e-Pages<br />

I.<br />

1. Factor = 3ab (a2 – 3ab + 9b) 2<br />

2. Factor = (m – n)(3m – 1)<br />

3. Factor = 4(u – 1)(2 – v)<br />

II.<br />

(1) To factor x2 + 5x + 6, I need two numbers that add<br />

up to 5 and have a product of 6.<br />

Thus, x2 + 5x + 6 = (x + 5)(x + 1).<br />

(2) To factor x2 – 2x – 3, I need two numbers that add<br />

up to –2 and have a product of –3.<br />

Thus, x2 – 2x – 3 = (x – 3)(x + 1).<br />

(3) To factor x2 – 8x + 15, I need two numbers that<br />

add up to –8 and have a product of 15.<br />

Thus, x2 – 8x + 15 = (x – 3)(x – 5).<br />

III.<br />

1. (x + 7) and (x + 4)<br />

2. (x + 3) 2<br />

3. (x + 4) and (x – 1)<br />

4. (4x – 1) and (3x – 4)<br />

5. a b<br />

c<br />

d<br />

8

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