How Large Is One Zillion? - Diwa Learning Systems
How Large Is One Zillion? - Diwa Learning Systems How Large Is One Zillion? - Diwa Learning Systems
Answers to Exercises How Large Is One Zillion? Exercise 1 A. Factoring xm xn = xm–n , x ≠ 0 Addition of Integers x –n = 1 xn , x ≠ 0 ( x y ) n = xn y n (xm ) n = xmn Expanding the power B. Expressing numbers in terms of exponents Exercise 2 (xm ) n = xmn and x0 = 1, x ≠ 0 x m · x n = x m+n Addition of integers x –n = 1 x n , x ≠ 0 and x 0 = 1, x ≠ 0 1 2 3 4 5 0 1 6 8 9 4 6 7 . 3 2 . 8 1 8 9 10 0 2 0 2 4 0 12 11 0 4 4 8 0 0 1 4 4 0 13 14 0 1 1 3 0 15 16 17 0 8 1 2 0 0 18 19 20 4 3 . 3 0 0 21 22 1 0 6 4 4 0 Factor In Answer to the Preliminary Problem: 0, one of the factors is (x – x) = 0 TATSULOK Second Year Vol. 11 No. 3 e-Pages I. 1. Factor = 3ab (a2 – 3ab + 9b) 2 2. Factor = (m – n)(3m – 1) 3. Factor = 4(u – 1)(2 – v) II. (1) To factor x2 + 5x + 6, I need two numbers that add up to 5 and have a product of 6. Thus, x2 + 5x + 6 = (x + 5)(x + 1). (2) To factor x2 – 2x – 3, I need two numbers that add up to –2 and have a product of –3. Thus, x2 – 2x – 3 = (x – 3)(x + 1). (3) To factor x2 – 8x + 15, I need two numbers that add up to –8 and have a product of 15. Thus, x2 – 8x + 15 = (x – 3)(x – 5). III. 1. (x + 7) and (x + 4) 2. (x + 3) 2 3. (x + 4) and (x – 1) 4. (4x – 1) and (3x – 4) 5. a b c d 8
- Page 1 and 2: How Large Is One Zillion? By Divina
- Page 3: ACROSS 2. (a8 ) 20 · a8 = a ??? x3
Answers to Exercises<br />
<strong>How</strong> <strong>Large</strong> <strong>Is</strong> <strong>One</strong> <strong>Zillion</strong>?<br />
Exercise 1<br />
A. Factoring<br />
xm xn = xm–n , x ≠ 0<br />
Addition of Integers<br />
x –n = 1<br />
xn , x ≠ 0<br />
( x<br />
y ) n<br />
= xn<br />
y n<br />
(xm ) n<br />
= xmn Expanding the power<br />
B. Expressing numbers in terms of<br />
exponents<br />
Exercise 2<br />
(xm ) n<br />
= xmn and x0 = 1, x ≠ 0<br />
x m · x n = x m+n<br />
Addition of integers<br />
x –n = 1<br />
x n , x ≠ 0 and x 0 = 1, x ≠ 0<br />
1 2 3 4 5<br />
0 1 6 8 9 4<br />
6 7<br />
. 3 2 . 8 1<br />
8 9 10<br />
0 2 0 2 4 0<br />
12<br />
11<br />
0 4 4 8 0<br />
0 1 4 4 0<br />
13 14<br />
0 1 1 3 0<br />
15 16 17<br />
0 8 1 2 0 0<br />
18 19 20<br />
4 3 . 3 0 0<br />
21 22<br />
1 0 6 4 4 0<br />
Factor In<br />
Answer to the Preliminary Problem:<br />
0, one of the factors is (x – x) = 0<br />
TATSULOK Second Year Vol. 11 No. 3 e-Pages<br />
I.<br />
1. Factor = 3ab (a2 – 3ab + 9b) 2<br />
2. Factor = (m – n)(3m – 1)<br />
3. Factor = 4(u – 1)(2 – v)<br />
II.<br />
(1) To factor x2 + 5x + 6, I need two numbers that add<br />
up to 5 and have a product of 6.<br />
Thus, x2 + 5x + 6 = (x + 5)(x + 1).<br />
(2) To factor x2 – 2x – 3, I need two numbers that add<br />
up to –2 and have a product of –3.<br />
Thus, x2 – 2x – 3 = (x – 3)(x + 1).<br />
(3) To factor x2 – 8x + 15, I need two numbers that<br />
add up to –8 and have a product of 15.<br />
Thus, x2 – 8x + 15 = (x – 3)(x – 5).<br />
III.<br />
1. (x + 7) and (x + 4)<br />
2. (x + 3) 2<br />
3. (x + 4) and (x – 1)<br />
4. (4x – 1) and (3x – 4)<br />
5. a b<br />
c<br />
d<br />
8