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Lectures on Representations of Quivers by William Crawley-Boevey ...

Lectures on Representations of Quivers by William Crawley-Boevey ...

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§4. Dynkin and Euclidean diagrams<br />

In this secti<strong>on</strong> we give the classificati<strong>on</strong> <strong>of</strong> graphs into Dynkin,<br />

Euclidean, and ’wild’ graphs, and in the first two cases we study the<br />

corresp<strong>on</strong>ding root system.<br />

DEFINITIONS.<br />

Let be finite graph with vertices {1,..,n}. We allows loops and multiple<br />

edges, so that is given <strong>by</strong> any set <strong>of</strong> natural numbers<br />

n = n = the number <strong>of</strong> edges between i and j.<br />

ij ji<br />

i¤<br />

n 2<br />

i=1 i j ij i j<br />

Let q(¤ ) = ¤ ¤ - ¤ n ¤¢¤<br />

n<br />

Let (-,-) be the symmetric bilinear form <strong>on</strong> ¦ with<br />

§ ¨©<br />

(i£ -n<br />

ij<br />

( , ) =<br />

i j<br />

2 - 2n<br />

ii<br />

j)<br />

(i=j)<br />

where<br />

i<br />

th<br />

is the i coordinate vector.<br />

Note that knowledge <strong>of</strong> any <strong>on</strong>e <strong>of</strong> , q or (-,-) determines the others,<br />

1<br />

since q(¤ ) = (¤ ,¤ ) and (¤ ,¥ ) = q(¤ +¥ )-q(¤ )-q(¥ ).<br />

2<br />

If Q is a quiver and is its underlying graph, then (-,-) and q are the<br />

same as before. The bilinear form , however, depends <strong>on</strong> the<br />

orientati<strong>on</strong> <strong>of</strong> Q.<br />

n<br />

We say q is positive definite if q(¤ )>0 for all 0£ ¤ ¡ ¦ .<br />

n<br />

We say q is positive semi-definite if q(¤ )£ 0 for all ¤ ¡ ¦ .<br />

n<br />

The radical <strong>of</strong> q is rad(q) = {¤ ¡ ¦ ¢ (¤ ,-) = 0}.<br />

n n<br />

We have a partial ordering <strong>on</strong> ¦ given <strong>by</strong> ¤¦¤ ¥ if ¥ -¤ ¡ £ .<br />

n<br />

We say that ¤ ¡ ¦ is sincere if each comp<strong>on</strong>ent is n<strong>on</strong>-zero.<br />

LEMMA. If is c<strong>on</strong>nected and ¥¦£ 0 is a n<strong>on</strong>-zero radical vector, then ¥ is<br />

n<br />

sincere and q is positive semi-definite. For ¤ ¡ ¦ we have<br />

q(¤ )=0 ¢¤ ¡¢¡ ¥ ¢¤ ¡ rad(q).<br />

15

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