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Lectures on Representations of Quivers by William Crawley-Boevey ...

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THE ACTION.<br />

GL(¤ Rep(¤ ) acts <strong>on</strong> ) <strong>by</strong> c<strong>on</strong>jugati<strong>on</strong>. Explicitly<br />

(gx) = g x g<br />

-1<br />

t(¢ ) ¢ s(¢ ) ¢<br />

g¡ GL(¤ for ) x¡ Rep(¤ and ).<br />

If x,y¡ Rep(¤ ), then the set <strong>of</strong> A-module isomorphisms R(x) ¡ R(y) can be<br />

identified with {g¡ GL(¤ ) ¢ gx=y}. It follows that<br />

(1) Stab (x) Aut (R(x)).<br />

GL(¤ ) A<br />

(2) There is a 1-1 corresp<strong>on</strong>dence between isoclasses <strong>of</strong> representati<strong>on</strong>s X<br />

with dimensi<strong>on</strong> vector ¤ and orbits, given <strong>by</strong> O = {x¡ Rep(¤ ) ¢ R(x) X}. To<br />

X<br />

see this we <strong>on</strong>ly need to realize that every representati<strong>on</strong> <strong>of</strong> dimensi<strong>on</strong><br />

vector ¤ is isomorphic to some R(x), which follows <strong>on</strong> choosing a basis.<br />

REMARKS.<br />

(1) Invariant Theory is about polynomial and rati<strong>on</strong>al maps § :Rep(¤ ) ¡ k<br />

which are c<strong>on</strong>stant <strong>on</strong> GL(¤ )-orbits. For example, if a = ¢ ...¢ is an<br />

1 m<br />

oriented cycle, we have a polynomial invariant<br />

f (x) = Trace(x x ...x ),<br />

a ¢ ¢ ¢<br />

1 2 m<br />

and more generally if (T) is the characteristic polynomial <strong>of</strong> ¤ , we have<br />

¤<br />

i<br />

f (x) = Coefficient <strong>of</strong> T<br />

ai<br />

in<br />

x x ...x<br />

(T).<br />

1 2 m<br />

(2) If char k=0, then any polynomial invariant can be expressed as a<br />

¢ ¢ ¢<br />

polynomial in the f . This has been proved <strong>by</strong> Sibirski and Procesi in case<br />

a<br />

Q has <strong>on</strong>ly <strong>on</strong>e vertex, and in general can be found in L.Le Bruyn &<br />

C.Procesi, Semisimple representati<strong>on</strong>s <strong>of</strong> quivers, Trans. Amer. Math. Soc.<br />

317 (1990), 585-598.<br />

(3) If char k£ 0 and Q has <strong>on</strong>ly <strong>on</strong>e vertex, any polynomial invariant can be<br />

expressed as a polynomial in the f . This is recent work <strong>of</strong> S.D<strong>on</strong>kin.<br />

ai<br />

Presumably the restricti<strong>on</strong> <strong>on</strong> Q is unnecessary.<br />

12

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