This Rigger's Handbook is dedicated to Theodore C - Igor Chudov
This Rigger's Handbook is dedicated to Theodore C - Igor Chudov
This Rigger's Handbook is dedicated to Theodore C - Igor Chudov
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YOUR SLING AND RIGGING SPECIALIST<br />
RATIO FOR RATIO FOR<br />
NUMBER BRONZE ANTI-FRICTION<br />
OF PARTS BUSHED BEARING<br />
OF LINE SHEAVES SHEAVES<br />
1 .96 .98<br />
2 1.87 1.94<br />
3 2.75 2.88<br />
4 3.59 3.81<br />
5 4.39 4.71<br />
6 5.16 5.60<br />
7 5.90 6.47<br />
8 6.60 7.32<br />
9 7.27 8.16<br />
10 7.91 8.98<br />
11 8.52 9.79<br />
12 9.11 10.6<br />
13 9.68 11.4<br />
14 10.2 12.1<br />
15 10.7 12.9<br />
16 11.2 13.6<br />
17 11.7 14.3<br />
18 12.2 15.0<br />
19 12.6 15.7<br />
20 13.0 16.4<br />
21 13.4 17.0<br />
22 13.8 17.7<br />
23 14.2 18.3<br />
24 14.5 18.9<br />
HOW TO FIGURE LINE PARTS<br />
HEADQUARTERS: 55 James E. Casey Drive • Buffalo, NY 14206 PHONE: 716.826.2636 FAX: 716.826.4412 www.hanessupply.com<br />
137<br />
Wire Ropes<br />
To help figure the number of parts of line <strong>to</strong> be used for<br />
a given load or the line pull required for a given load, the<br />
following ratio table <strong>is</strong> provided with examples of how <strong>to</strong><br />
use it:<br />
1<br />
PART<br />
OF LINE<br />
2<br />
PARTS<br />
OF LINE<br />
3<br />
PARTS<br />
OF LINE<br />
USING THE RATIO TABLE RATIO FORMULA<br />
TOTAL LOAD TO BE LIFTED<br />
SINGLE LINE PULL IN POUNDS<br />
Example:<br />
To find the number of parts of line needed<br />
when weight of load and single line pull <strong>is</strong><br />
establ<strong>is</strong>hed.<br />
Sample Problem:<br />
72,480 lbs. (load <strong>to</strong> be lifted)<br />
8,000 lbs. (single line pull) = 9.06 RATIO<br />
Refer <strong>to</strong> ratio 9.06 in table or number nearest<br />
<strong>to</strong> it, then check column under heading<br />
"Number of Parts of Line"... 12 parts of line <strong>to</strong><br />
be used for th<strong>is</strong> load.<br />
= RATIO<br />
4<br />
PARTS<br />
OF LINE<br />
5<br />
PARTS<br />
OF LINE<br />
Example:<br />
To find single line pull needed when weight of<br />
load and number of parts of line are<br />
establ<strong>is</strong>hed.<br />
Sample Problem:<br />
68,000 lbs. (load <strong>to</strong> be lifted)<br />
6.60 (ratio of 8 part line)<br />
= 10,300 lbs. (single line pull)<br />
10,300 lbs. single line pull required <strong>to</strong> lift th<strong>is</strong><br />
load on 8 parts of line.