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This Rigger's Handbook is dedicated to Theodore C - Igor Chudov

This Rigger's Handbook is dedicated to Theodore C - Igor Chudov

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YOUR SLING AND RIGGING SPECIALIST<br />

RATIO FOR RATIO FOR<br />

NUMBER BRONZE ANTI-FRICTION<br />

OF PARTS BUSHED BEARING<br />

OF LINE SHEAVES SHEAVES<br />

1 .96 .98<br />

2 1.87 1.94<br />

3 2.75 2.88<br />

4 3.59 3.81<br />

5 4.39 4.71<br />

6 5.16 5.60<br />

7 5.90 6.47<br />

8 6.60 7.32<br />

9 7.27 8.16<br />

10 7.91 8.98<br />

11 8.52 9.79<br />

12 9.11 10.6<br />

13 9.68 11.4<br />

14 10.2 12.1<br />

15 10.7 12.9<br />

16 11.2 13.6<br />

17 11.7 14.3<br />

18 12.2 15.0<br />

19 12.6 15.7<br />

20 13.0 16.4<br />

21 13.4 17.0<br />

22 13.8 17.7<br />

23 14.2 18.3<br />

24 14.5 18.9<br />

HOW TO FIGURE LINE PARTS<br />

HEADQUARTERS: 55 James E. Casey Drive • Buffalo, NY 14206 PHONE: 716.826.2636 FAX: 716.826.4412 www.hanessupply.com<br />

137<br />

Wire Ropes<br />

To help figure the number of parts of line <strong>to</strong> be used for<br />

a given load or the line pull required for a given load, the<br />

following ratio table <strong>is</strong> provided with examples of how <strong>to</strong><br />

use it:<br />

1<br />

PART<br />

OF LINE<br />

2<br />

PARTS<br />

OF LINE<br />

3<br />

PARTS<br />

OF LINE<br />

USING THE RATIO TABLE RATIO FORMULA<br />

TOTAL LOAD TO BE LIFTED<br />

SINGLE LINE PULL IN POUNDS<br />

Example:<br />

To find the number of parts of line needed<br />

when weight of load and single line pull <strong>is</strong><br />

establ<strong>is</strong>hed.<br />

Sample Problem:<br />

72,480 lbs. (load <strong>to</strong> be lifted)<br />

8,000 lbs. (single line pull) = 9.06 RATIO<br />

Refer <strong>to</strong> ratio 9.06 in table or number nearest<br />

<strong>to</strong> it, then check column under heading<br />

"Number of Parts of Line"... 12 parts of line <strong>to</strong><br />

be used for th<strong>is</strong> load.<br />

= RATIO<br />

4<br />

PARTS<br />

OF LINE<br />

5<br />

PARTS<br />

OF LINE<br />

Example:<br />

To find single line pull needed when weight of<br />

load and number of parts of line are<br />

establ<strong>is</strong>hed.<br />

Sample Problem:<br />

68,000 lbs. (load <strong>to</strong> be lifted)<br />

6.60 (ratio of 8 part line)<br />

= 10,300 lbs. (single line pull)<br />

10,300 lbs. single line pull required <strong>to</strong> lift th<strong>is</strong><br />

load on 8 parts of line.

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