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S.N. Lahiri et al. / Journal of Statistical Plann<strong>in</strong>g and Inference 137 (2007) 3570 –3590 3585<br />

Next consider <strong>the</strong> case where 0 ∈[b− h/2,b+ h/2). Then, by Taylor’s expansion,<br />

<br />

<br />

b−h/2 <br />

<br />

h(b) − (x) dx<br />

h3 | ′′ (0)|/24.<br />

b−h/2<br />

Now us<strong>in</strong>g similar arguments for <strong>the</strong> case ‘ √ 3 ∈ (b − h/2,b + (j0 + 1 2 )h)’ and us<strong>in</strong>g <strong>the</strong> above bounds, one can<br />

complete <strong>the</strong> proof of <strong>the</strong> lemma. <br />

Proof of Theorem 1. Let r ∈ N be an <strong>in</strong>teger such that (2.4) holds. S<strong>in</strong>ce r will be held fixed all through <strong>the</strong> proof,<br />

we shall drop r from <strong>the</strong> notation for simplicity, and write fr = f , r = , pr = p, qr = q, nr − n, etc. First, suppose<br />

that f 1 2 . Consider <strong>the</strong> case x 0. Let ˜xk = xk/ √ 1 − f = (k − np)/, k = 0, 1,...,n. Def<strong>in</strong>e<br />

and<br />

K0 = sup{k ∈ Z+ :˜xk 0},<br />

K1 = <strong>in</strong>f{k ∈ Z+ :˜xk − 1},<br />

K2 = <strong>in</strong>f{k ∈ Z+ :˜xk − }<br />

Jx =⌊np + x⌋, x ∈ R,<br />

where ≡ r ∈ (0, 1 2 ] is as <strong>in</strong> (2.3). Note that by def<strong>in</strong>ition,<br />

K1 − 1

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