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Chapter 1 LINEAR COMPLEMENTARITY PROBLEM, ITS ...

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10 <strong>Chapter</strong> 1. Linear Complementarity Problem, Its Geometry, and Applications<br />

8<br />

9<br />

>: u><br />

;<br />

v<br />

8<br />

>: u<br />

9<br />

> ><br />

v =<br />

0<br />

8<br />

>:<br />

8<br />

9<br />

9<br />

0 ;AT ><br />

A 0<br />

8 >: x><br />

=<br />

y<br />

>: x<br />

9 8<br />

> ><br />

y =<br />

0 and >: u<br />

v<br />

8<br />

>: cT<br />

9<br />

;b<br />

9<br />

><br />

9<br />

> T 8 >: x<br />

y<br />

> =0:<br />

(1:10)<br />

Conversely, if u, v, x, y together satisfy all the conditions in (1.10), x is an optimum<br />

solution of (1.9). In (1.10) all the vectors and matrices are written in partitioned<br />

form. For example, ; u<br />

v is the vector (u1:::uNv1:::vm) T . If n = m + N,<br />

w =<br />

8<br />

>: u<br />

v<br />

9<br />

> z =<br />

8<br />

>: x<br />

y<br />

9<br />

> M =<br />

8<br />

>:<br />

0 ;AT<br />

A 0<br />

9<br />

> q =<br />

8<br />

>: cT<br />

9<br />

> <br />

;b<br />

(1.10) is seen to be an LCP of order n of the type (1.6) to (1.8). Solving the LP (1.9)<br />

can be achieved by solving the LCP (1.10).<br />

Also, the various complementary pairs of variables in the LCP (1.10) are exactly<br />

those in the pair of primal, dual LPs (1.9) and its dual. As an example consider the<br />

following LP.<br />

Minimize ;13x1 +42x2<br />

Subject to 8x1 ; x2 + 3x2 > = ;16<br />

; 3x1 + 2x2 ; 13x3 > = 12<br />

xj > =<br />

0 j = 1 2 3:<br />

Let (v1y1), (v2y2) denote the nonnegative slack variable, dual variable respectively,<br />

associated with the two primal constraints in that order. Let u1, u2, u3 denote the<br />

nonnegative dual slack variable associated with the dual constraint corresponding to<br />

the primal variable x1, x2, x3, in that order. Then the primal and dual systems<br />

together with the complementary slackness conditions for optimality are<br />

8x1 ; x2 + 3x3 ; v1 = ;16<br />

;3x1 + 2x2 ; 13x3 ; v2 = 12<br />

8y1 ; 3y2 + u1 = ;13<br />

; y1 + 2y2 + u2 = 42<br />

3y1 ; 13y2 + u3 = 0:<br />

xjujyivi > =<br />

0 for all i j.<br />

xjuj = yivi =0 for all i j.

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