1. Xtra Edge February 2012 - Career Point

µ 0I1I
2
F2 = B1I2 =
[Q F = BI l, Here l = 1]
2πr
By Fleming's left hand rule direction of F2 is away
from conductor AB.
Similarly the current I2 will create a field B2 at Q
directed inward which in turn will create force/length
F1
µ 0I1I
2
F1 = B2I1 =
2πr
By Fleming's left hand rule, the direction of F1 is
away from the conductor CD. Hence the two
conductors repel each other.
Definition of Ampere If I1 = I2 = 1A, and r = 1m,
then
−7
0 4π×
10
−7
−1
2 10 Nm
µ
F = = = ×
2π
2π
Thus one ampere is that current which on flowing
through each of the two parallel uniform linear
conductors placed in free space at a distance of one
meter from each other produces between them a
force of 2 × 10 –7 N per metre of their lengths.
CHEMISTRY
1. CH3–CH2–CH=CH2 + HCl →
CH − CH
2. (ii) > (iii) > (i) > (iv)
3
2
− CH − CH
3. By fehling solution, tollen reagent etc.
4. Amino acid are compound containing amino group
and carboxylic group.
Structure of alanine is –
+
H3N–CH–COO –
CH3
5. Movement of colloidal particles towards opposite
terminal takes place which is called as
electrophoresis.
6. It is a stoichiometric defect in which an ion (cation)
get displaced from its position and get arranged as an
interstitial particle it is called Frenkel defect in this
defect a vacancy or interstitial defect are formed
simultaneously. Due to Frenkel defect.
(i) Density remains same
(ii) Electrical conductivity improved
7. No of particle are different in sugar and NaCl. As
dissociation in NaCl takes place.
8. Methyl 3-bromo 2-oxo butanoate
|
Cl
3
9. (i) Sandmayer reaction.
(ii) Kuchrous reaction
CH ≡ CH ⎯→ CH2 = CH
|
OH
XtraEdge for IIT-JEE 92 FEBRUARY 2012
—Cl
10. (i) C H − N=
C + 2HOH
⎯⎯→
(ii)
2 5
Ethyl isocyanide
Aniline
H
H
NH
+ Cl–C–CH3
Acetyl chloride
H
+
Hydrolysis
CH3 – CHO
C2
H5NH2
+ HCOOH
Ethyl amine
H
∆
Base
O
N–C–CH3 + HCl
N-Phenylethanamide
11. The given reaction will be as
O
H2O
CH3CH2–C–H + CH3MgBr CH3CH2–CH–CH3
(A)
OH
12.
CH3–CH–CH–CH3
Br2 CH3CH=CH–CH3
Br Br
(B)
(C)
Alc. KOH
CH3–C≡C–CH3
(D)
O
| |
Structural formula of A : CH CH − C−
H
Structural formula of B : CH3CH=CH–CH3
Structural formula of C : CH3–CH–CH–CH3
Br Br
Structural formula of D : CH3–C≡C–CH3
(i)
NH2
Aniline
+ CH3Cl + 3 KOH
Chloroform
NC
Carbylamine
3
2
∆
+ 3 KCl + 3 H2O
–H2O
H2SO4