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1. Xtra Edge February 2012 - Career Point

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<strong>1.</strong> If<br />

MATHS<br />

4<br />

sin α<br />

8<br />

a<br />

+<br />

4<br />

cos α<br />

8<br />

b<br />

=<br />

1<br />

a + b<br />

sin α cos α 1<br />

+ =<br />

3<br />

3<br />

a b ( a + b)<br />

3<br />

, show that<br />

a + b 4 a + b 4<br />

Sol. Here sin α + cos α = 1<br />

a<br />

b<br />

or sin 4 α + cos 4 b 4 a 4<br />

α + sin α + cos α = 1<br />

a b<br />

or (sin 2 α + cos 2 α) 2 – 2 sin 2 α . cos 2 α<br />

b 4 a 4<br />

+ sin α + cos α = 1<br />

a b<br />

or<br />

or<br />

∴<br />

⎛<br />

⎜<br />

⎝<br />

⎛<br />

⎜<br />

⎝<br />

b<br />

a<br />

b<br />

a<br />

2<br />

sin<br />

sin<br />

2<br />

⎞<br />

α⎟<br />

⎟<br />

⎠<br />

2<br />

α –<br />

.<br />

b 2 a 2<br />

– 2 . sin α . cos α<br />

a b<br />

a<br />

b<br />

cos<br />

b 2 a 2<br />

sin α = cos α<br />

a b<br />

2<br />

⎞<br />

α⎟<br />

⎟<br />

⎠<br />

2<br />

⎛<br />

+ ⎜<br />

⎝<br />

= 0<br />

or sin 2 a 2<br />

α = cos α<br />

b<br />

2<br />

2<br />

2<br />

sin α cos α sin α + cos<br />

∴ = =<br />

a b a + b<br />

∴ sin 2 a<br />

α =<br />

a + b<br />

, cos2 b<br />

α =<br />

a + b<br />

8<br />

sin α cos α<br />

∴ + =<br />

3<br />

3<br />

a b<br />

=<br />

a<br />

( a + b<br />

4<br />

)<br />

+<br />

8<br />

b<br />

( a + b<br />

1<br />

3<br />

a .<br />

4<br />

)<br />

a<br />

4<br />

( a + b)<br />

=<br />

4<br />

a + b<br />

( a + b<br />

2<br />

4<br />

)<br />

+<br />

a<br />

b<br />

α<br />

2<br />

cos<br />

1<br />

3<br />

b .<br />

=<br />

2<br />

⎞<br />

α⎟<br />

= 0<br />

⎟<br />

⎠<br />

b<br />

4<br />

( a + b)<br />

1<br />

( a + b)<br />

2. Let [x] stands for the greatest integer function find<br />

2<br />

3 x + sin x<br />

the derivative of f(x) = ( x + [ x + 1])<br />

, where it<br />

exists in (1, <strong>1.</strong>5). Indicate the point(s) where it does<br />

not exist. Give reason(s) for your conclusion.<br />

Students' Forum<br />

Expert’s Solution for Question asked by IIT-JEE Aspirants<br />

3<br />

4<br />

Sol. The greatest integer [x 3 + 1] takes jump from 2 to 3 at<br />

3 3<br />

2 and again from 3 to 4 at 3 in [1, <strong>1.</strong>5] and<br />

therefore it is discontinuous at these two points. As a<br />

result the given function is discontinuous at 3 2 and<br />

hence not differentiable.<br />

To find the derivative at other points we write :<br />

in (1, 3 2 ), f(x) = ( x + 2)<br />

⇒ f ´(x) = ( x + 2)<br />

2<br />

x + sin x−1<br />

2<br />

x + sin x<br />

{x 2 + sin x + (x + 2) (2x + cos x) log (x + 2)}<br />

2<br />

x + sin x<br />

in ( 3 2, 3 3 ), f(x) = ( x + 3)<br />

,<br />

f ´(x) = (<br />

2<br />

x + sin x−1<br />

x + 3)<br />

{x 2 + sin x<br />

+ (2x + cos x) (x + 3) × loge (x + 3)}<br />

2<br />

x + sin x<br />

in ( 3 5 , <strong>1.</strong>5), f(x) = ( x + 4)<br />

,<br />

2<br />

x + sin x−1<br />

x , {x 2 + sin x + (2x + cos x)<br />

f ´(x) = ( + 4)<br />

(x + 4) × loge(x + 4)}<br />

3. The decimal parts of the logarithms of two numbers<br />

taken at random are found to six places of decimal.<br />

What is the chance that the second can be subtracted<br />

from the first without "borrowing"?<br />

Sol. For each column of the two numbers,<br />

n(S) = number of ways to fill the two places by the<br />

digits 0, 1, 2, ... , 9<br />

= 10 × 10 = 100.<br />

x<br />

× × × × × ×<br />

y<br />

× × × × × ×<br />

Let E be the event of subtracting in a column without<br />

borrowing. If the pair of digits be (x, y) in the column<br />

where x is in the first number and y is in the second<br />

number then<br />

E = {(0, 0), (1, 0), (2, 0), .. ,(9, 0),<br />

(1, 1), (2, 1), ..., (9, 1),<br />

(2, 2), (3, 2), ..., (9, 2),<br />

(3, 3), (4, 3), ..., (9, 3),<br />

......<br />

(8, 8), (9, 8),<br />

(9, 9)}<br />

<strong>Xtra</strong><strong>Edge</strong> for IIT-JEE 40 FEBRUARY <strong>2012</strong>

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