1. Xtra Edge February 2012 - Career Point

Step 5. 1 gram equivalent acid neutralizes 1 gram
equivalent of base.
∴ 0.6 + 0.36 + 0.51 V H = 3.003
2SO4
Solving , V H = 4 ml
2SO4
Step 6. 1000 ml of 1 M H2SO4 contains
= 96 g SO4 2– ions
96 × 17×
4
∴ 4ml of 17 M H2SO4 contains =
1000
= 6.528g SO4 2– ions
9. The equilibrium constant Kp of the reaction
2SO2(g) + O2(g) 2SO3(g) is 900 atm –1 at
800 K. A mixture containing SO3 and O2 having
initial partial pressures of 1 atm and 2 atm,
respectively, is heated at constant volume to
equilibrate. Calculate the pressure of each gas at
800 K. [IIT- 1989]
Sol. Since to start with SO2 is not present, it is expected
that some of SO3 will decompose to give SO2 and
O2 at equilibrium. If 2x is the partial pressure of
SO3 that is decreased at equilibrium, we would
have
2SO2(g) + O2(g) 2SO3(g)
t = 0 0 2 atm 1 atm
teq 2x 2 atm + x 1 atm – 2x
2
( p )
2
SO3
( 1 atm − 2x)
Hence, Kp =
=
2
2
( pSO
) ( p )
2 O ( 2x)
( 2 atm + x)
2
= 900 atm –1
Assuming x