1. Xtra Edge February 2012 - Career Point
1. Xtra Edge February 2012 - Career Point 1. Xtra Edge February 2012 - Career Point
I1 I2 Since I1 is an odd function therefore I1 = 0 π/ 4 I = π/ 4 ∫ – π/ 4 π/ 4 = π/ 4 ∫ 2 1 – π/ 4 π/ 4 dx ⎛ ⎜ 1– tan 2 – ⎜ ⎝1 + tan + ( sec 2 x 2 2 x ⎞ ⎟ x ⎟ ⎠ 2 3 tan x) sec x = 2 π/ 4 ∫ [Q f(x) is even function] 2 2 1 + ( 3 tan x) 0 2 Let 3 tan x = t ⇒ sec 2 dt x dx = 3 dt / 3 = ∫ 2 2 1+ t π 3 0 = ( ) 3 – 1 / 2 3 tan t π = 26. The given lines are → r = ( kˆ î – 2jˆ + 3 ) + t ( kˆ – î + jˆ – 2 ) and → r = ( kˆ î – jˆ – ) + s ( kˆ î + 2jˆ – 2 ) Here → 1 → 2 – 0 2 π a = kˆ î – 2jˆ + 3 ; → b 1 = kˆ – î + jˆ – 2 a = kˆ î jˆ – ; → b = kˆ î + 2 jˆ – 2 b × → b = ∴ → 1 2 î – 1 1 jˆ 1 2 k ˆ – 2 – 2 The S.D. between the gives lines = = → → ( b1× b2 ).( a1 – a 2 ) | b × b | 2 2 1 4 + 12 + 4 2 → 2 2 + 3 → = 8 = 29 2 6 3 = kˆ 2 î – 4 jˆ – 3 k | ˆ k) | 2î – 4jˆ – 3 ˆ k).( jˆ – 4 ˆ ( 2î – 4 jˆ – 3 27. Part I st Let x kg and y kg. of fertilizer A and B be mixed by the farmer. Then LPP is Minimize : C = 5x + 8y subject to the constraints 10 5 x + y ≥ 7 ⇔ 2x + y ≥ 140 100 100 6 10 x + y ≥ 7 ⇔ 3x + 5y ≥ 350 100 100 x ≥ 0, y ≥ 0 y (1) (0, 140)B D XtraEdge for IIT-JEE 100 FEBRUARY 2012 O (50, 40) P A C ⎡350 ⎤ ⎢ , 0⎥ ⎣ 3 ⎦ (2) Draw the lines 2x + y = 140 ..... (1) 3x + 5y = 350 ..... (2) The shaded unbounded region is the feasible region. These line meet at P(50, 40) Now value of c = 5x + 8y ⎡350 ⎤ 1750 1 at C ⎢ , 0⎥ , is = 583 ⎣ 3 ⎦ 3 3 at P(50, 40) is 570 at B(0, 140) is 1120 ∴ The cost is minimum at P(50, 40) This occurs when 50 kg of type & fertilizer and 40 kg of type B fertilizer are mixed to the meet the requirement. Part 2 nd Let x and y represent the number of tables and chairs respectively that the dealer sells and P be the profit of the dealer. Then the required LPP is . Maximize: P = 50x + 15y Subject to the constraints 500x + 200 y ≤ 10,000 ⇔ 5x + 2y ≤ 100 x + y = 60 ....(1) 5x + 2y = 100 .... (2) y D (0, 50) B(0, 60) A(60, 0) x O C (20, 0) (1) (2) A shaded region OCD is the feasible region. Now P = 50x + 15y At O, value of P is O At C, value of P is 50 × 20 = 1,000 At D, value of P is 15 × 50 = 750 ∴ Profit is maximum at C (20, 0) x
28. x x y ∴ x → side of square y → rad. of circle ∴ 4x + 2πy = 36 ..... (1) Now area A = x 2 + πy 2 A = x 2 ⎛18 – 2x ⎞ + π ⎜ ⎟ [From (1)] ⎝ π ⎠ dA 4 = 2x – (18 – 2x) dx π 2 d A = 2 + 8/π > 0 ⇒ min 2 dx m area Form min m dA area = 0 dx 36 ⇒ x = π + 4 18 From (1) , y = π + 4 144 Length of one piece = 4x = π + 4 36π Length of other piece = 2πy = π + 4 1 29. Let = u ; x 2 1 1 = v; = w y z Given equation can be written in form ⎡ 2 3 10 ⎤ ⎡ u ⎤ ⎡4⎤ ⎢ ⎥ ⎢ 4 – 6 5 ⎢ ⎥ ⎥ ⎢ v ⎥ = ⎢ ⎥ ⎢ 1 ⎥ ⎢⎣ 6 9 – 20 ⎥⎦ ⎢⎣ w⎥⎦ ⎢⎣ 2⎥⎦ A ⋅ X = B X = A –1 ⋅ B Adj( A) X = . B, |A| = 1200 | A | X = ⎡ 75 ⎢ ⎢ 110 ⎢⎣ 72 150 – 100 0 1200 75 30 – 24 ⎤ ⎡4⎤ ⎥ . ⎢ 1 ⎥ ⎥ ⎢ ⎥ ⎥⎦ ⎢⎣ 2⎥⎦ ⎡600⎤ ⎡ u ⎤ ⎢ X = ⎢ ⎥ 400 ⎥ ⎡1/ 2⎤ ⎢ v ⎥ = ⎢ ⎥ = ⎢ ⎥ ⎢240⎥ ⎢ 1/ 3 ⎥ ⎢⎣ w⎥ ⎣ ⎦ ⎦ ⎢ ⎥ 1200 ⎣1/ 5⎦ u = 1/2 ⇒ x = 2 v = 1/3 ⇒ y = 3 w = 1/5 ⇒ z = 5 At a Glance Some Important Practical Units 1. Par sec : It is the largest practical unit of distance. 1 par sec = 3.26 light year 2. X-ray unit : It is the unit of length. 1 X-ray unit = 10 –13 m 3. Slug : It is the unit of mass. 1 slug = 14.59 kg 4. Chandra Shekhar limit : It is the largest practical unit of mass. 1 Chandra Shekhar limit = 1.4 × Solar mass 5. Shake : It is the unit of time. 1 Shake = 10 –6 second 6. Barn : It is the unit of area. 1 barn = 10 –28 m 2 7. Cusec : It is the unit of water flow. 1 cusec = 1 cubic foot per second flow 8. Match No. : This unit is used to express velocity of supersonic jets. 1 match no. = velocity of sound = 332 m/sec. 9. Knot : This unit is used to express velocity of ships in water. 1 knot = 1.852 km/hour 10. Rutherford : It is the unit of radioactivity. 1 rutherford (rd) = 1 × 10 6 disintegrations/sec 11. Dalton : It is the unit of mass. 1 12 1 dalton = mass of C = 931 MeV 12 = 1 a.m.u. 12. Curie : It is the unit of radioactivity. 1 curie = 3.7 × 10 10 disintegration / sec XtraEdge for IIT-JEE 101 FEBRUARY 2012
- Page 51 and 52: R P ⊗ B O ω0 14. Magnitude of cu
- Page 53 and 54: XtraEdge for IIT-JEE 51 FEBRUARY 20
- Page 55 and 56: XtraEdge for IIT-JEE 53 FEBRUARY 20
- Page 57 and 58: 7. NaOH can be prepared by two meth
- Page 59 and 60: (C) X = 100 ml of SO2 at 1 bar, 25
- Page 61 and 62: 21. Column-I Column-II (A) If y = 2
- Page 63 and 64: (A) potential energy (PE) increases
- Page 65 and 66: 2. In the reaction 3 Cu + 8 HNO3
- Page 67 and 68: (D) P A T B (S) Pressure is increas
- Page 69 and 70: XtraEdge for IIT-JEE 67 FEBRUARY 20
- Page 71 and 72: 14. Derive the expression for the c
- Page 73 and 74: (a) temperature and (b) Pressure ?
- Page 75 and 76: should be bought to meet the requir
- Page 77 and 78: This work done is stored inside the
- Page 79 and 80: Use : It can be used to accelerate
- Page 81 and 82: 10. (i) (ii) Benzene H CH3 - C = O
- Page 83 and 84: NH3 NH3 NH3 Co +3 NH3 NH3 NH3 No un
- Page 85 and 86: 7. f(A) = A 2 - 5A + 7 I2 ⎡ 3 1
- Page 87 and 88: y 2 = - (2 - x) 2 + 9 This is the e
- Page 89 and 90: (0, 4) ( 2 3, 2) (4, 0) ⎡ 2 4 2
- Page 91 and 92: 15. X = ? Y = 20 Ω l1 = 40 cm l -
- Page 93 and 94: (i) Emission : - If radiations emit
- Page 95 and 96: OH (ii) + Br2 Phenol H2O 13. I st M
- Page 97 and 98: 28. (a) Acetylene is first oxidized
- Page 99 and 100: OR Let A → total of 8 in first th
- Page 101: = x 2 ⎡ ⎢ ⎢x ⎢ ⎣ 0 1 2 1
- Page 105 and 106: C 'XtraEdge for IIT-JEE IIT JEE bec
- Page 107 and 108: XtraEdge for IIT-JEE 105 FEBRUARY 2
28.<br />
x<br />
x<br />
y<br />
∴ x → side of square<br />
y → rad. of circle<br />
∴ 4x + 2πy = 36 ..... (1)<br />
Now area A = x 2 + πy 2<br />
A = x 2 ⎛18<br />
– 2x<br />
⎞<br />
+ π ⎜ ⎟ [From (1)]<br />
⎝ π ⎠<br />
dA 4<br />
= 2x – (18 – 2x)<br />
dx π<br />
2<br />
d A<br />
= 2 + 8/π > 0 ⇒ min 2<br />
dx<br />
m area<br />
Form min m dA<br />
area = 0<br />
dx<br />
36<br />
⇒ x =<br />
π + 4<br />
18<br />
From (1) , y =<br />
π + 4<br />
144<br />
Length of one piece = 4x =<br />
π + 4<br />
36π<br />
Length of other piece = 2πy =<br />
π + 4<br />
1<br />
29. Let = u ;<br />
x<br />
2<br />
1 1<br />
= v; = w<br />
y z<br />
Given equation can be written in form<br />
⎡ 2 3 10 ⎤ ⎡ u ⎤ ⎡4⎤<br />
⎢<br />
⎥<br />
⎢<br />
4 – 6 5<br />
⎢ ⎥<br />
⎥ ⎢<br />
v<br />
⎥<br />
=<br />
⎢ ⎥<br />
⎢<br />
1<br />
⎥<br />
⎢⎣<br />
6 9 – 20 ⎥⎦<br />
⎢⎣<br />
w⎥⎦<br />
⎢⎣<br />
2⎥⎦<br />
A ⋅ X = B<br />
X = A –1 ⋅ B<br />
Adj(<br />
A)<br />
X = . B, |A| = 1200<br />
| A |<br />
X =<br />
⎡ 75<br />
⎢<br />
⎢<br />
110<br />
⎢⎣<br />
72<br />
150<br />
– 100<br />
0<br />
1200<br />
75<br />
30<br />
– 24<br />
⎤ ⎡4⎤<br />
⎥<br />
.<br />
⎢<br />
1<br />
⎥<br />
⎥ ⎢ ⎥<br />
⎥⎦<br />
⎢⎣<br />
2⎥⎦<br />
⎡600⎤<br />
⎡ u ⎤ ⎢<br />
X =<br />
⎢ ⎥ 400<br />
⎥ ⎡1/<br />
2⎤<br />
⎢<br />
v<br />
⎥<br />
= ⎢ ⎥ =<br />
⎢ ⎥<br />
⎢240⎥<br />
⎢<br />
1/<br />
3<br />
⎥<br />
⎢⎣<br />
w⎥<br />
⎣ ⎦<br />
⎦<br />
⎢ ⎥<br />
1200<br />
⎣1/<br />
5⎦<br />
u = 1/2 ⇒ x = 2<br />
v = 1/3 ⇒ y = 3<br />
w = 1/5 ⇒ z = 5<br />
At a Glance<br />
Some Important Practical Units<br />
<strong>1.</strong> Par sec : It is the largest practical unit of<br />
distance.<br />
1 par sec = 3.26 light year<br />
2. X-ray unit : It is the unit of length.<br />
1 X-ray unit = 10 –13 m<br />
3. Slug : It is the unit of mass.<br />
1 slug = 14.59 kg<br />
4. Chandra Shekhar limit : It is the largest<br />
practical unit of mass.<br />
1 Chandra Shekhar limit = <strong>1.</strong>4 × Solar mass<br />
5. Shake : It is the unit of time.<br />
1 Shake = 10 –6 second<br />
6. Barn : It is the unit of area.<br />
1 barn = 10 –28 m 2<br />
7. Cusec : It is the unit of water flow.<br />
1 cusec = 1 cubic foot per second flow<br />
8. Match No. : This unit is used to express velocity<br />
of supersonic jets.<br />
1 match no. = velocity of sound<br />
= 332 m/sec.<br />
9. Knot : This unit is used to express velocity of<br />
ships in water.<br />
1 knot = <strong>1.</strong>852 km/hour<br />
10. Rutherford : It is the unit of radioactivity.<br />
1 rutherford (rd) = 1 × 10 6 disintegrations/sec<br />
1<strong>1.</strong> Dalton : It is the unit of mass.<br />
1 12<br />
1 dalton = mass of C = 931 MeV<br />
12<br />
= 1 a.m.u.<br />
12. Curie : It is the unit of radioactivity.<br />
1 curie = 3.7 × 10 10 disintegration / sec<br />
<strong>Xtra</strong><strong>Edge</strong> for IIT-JEE 101 FEBRUARY <strong>2012</strong>