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Q.19 In case of interference of two waves each of
intensity I0, the intensity at a point of
constructive interference will be -
(a) 4I0 for coherent source
(b) 2I0 for coherent source
(c) 4I0 for incoherent source
(d) 2I0 for incoherent source
(1) a, c (2) b, c (3) a, d (4) b, d
Q.20 Vibration magnetometer is used -
(a) For comparing the magnetic moment of two
magnet
(b) For comparing the magnetic field of two
magnet
(c) For measuring magnetic field and magnetic
moment of unknown magnet
(d) For measuring magnetic hardness of
ferromagnetic materials
(1) a, b, c (2) a, b, c, d (3) a, c, d (4) a, b, d
Q.21 Which is the application of transistor from
following ?
(a) Amplifier (b) Oscillator
(c) Switch (d) Rectifier
(1) a, b, c (2) a, b, c, d (3) a, c, d (4) a, b, d
Column Matching :
Q. 22 In fresenl diffraction
Column I Column II
(a) Radius of the n th half
period zone
(b) Area of the n th half
period zone
(c) Average distance of
the n th half period
zone from the point of
observation
Correct Match is -
(1) a → p, b → q, c → r
(2) a → q, b → p, c → r
(3) a → r, b → q, c → p
(4) None
λ
(p) b + (2n – 1)
4
(q) πbλ
(r) nb λ
Q.23 Acceleration due to gravity at surface of earth is
g. Its value is taken as practically constant.
Column I gives different situations and column II
gives values of acceleration due to gravity.
Match correct options.
Q.19 I0 rhozrk okyh nks rjaxks ds O;frdj.k dh fLFkfr esa]
lEiks"kh O;frdj.k ds ,d fcUnq ij rhozrk gksxh -
(a) dyk lEc) L=kksr ds fy, 4I0
(b) dyk lEc) L=kksr ds fy, 2I0
(c) dyk vlEc) L=kksr ds fy, 4I0
(d) dyk vlEc) L=kksr ds fy, 2I0
(1) a, c (2) b, c (3) a, d (4) b, d
Q.20 nksyu pqEcdRoekih mi;ksx fd;k tkrk gS -
(a) nks pqEcdksa ds pqEcdh; vk?kw.kksZ dh rqyuk ds
fy,
(b) nks pqEcdksa ds pqEcdh; {ks=kkssa dh rqyuk ds fy,
(c) vKkr pqEcd ds pqEcdh; {ks=k rFkk pqEcdh;
vk?kw.kZ ds ekiu ds fy,
(d) ykSg pqEcdh; inkFkksZ dh pqEcdh; dBksjrk ekiu
djus ds fy,
(1) a, b, c (2) a, b, c, d (3) a, c, d (4) a, b, d
Q.21 fuEufyf[kr esa ls dkSulk VªkaftLVj dk vuqiz;ksx gS?
(a) izo/kZd (b) nksfy=k
(c) fLop (d) fn"Vdkjh
LrEHk lqesfyr %
(1) a, b, c (2) a, b, c, d (3) a, c, d (4) a, b, d
Q. 22 Ýsuy foorZu esa
LrEHk I LrEHk II
(a) nosa v)Z vkorhZ dfVcU/k
dh f=kT;k
λ
(p) b + (2n – 1)
4
(b) nosa v)Z vkorhZ dfVcU/k
dk {ks=kQy
(q) πbλ
(c) izs{k.k fcUnq ls nosa v)Z (r) nb λ
vkorhZ dfVcU/k dh
vkSlr nwjh
lgh feyku gS -
(1) a → p, b → q, c → r
(2) a → q, b → p, c → r
(3) a → r, b → q, c → p
(4) dksbZ ugha
Q.23 i`Foh dh lrg ij xq:Roh; Roj.k g gSA bldk eku
izk;ksfxd :i ls fu;r fy;k tkrk gSA LrEHk I es
fHkUu fLFkfr;k¡ n'kkZbZ xbZ gS rFkk LrEHk II esa xq:Roh;
Roj.k ds eku gSA lgh fodYi dk feyku dhft,A
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