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Thus
Inserting the conduction resistances
into Equation 3.18 we get
Example 1
A two-layer wall consists of the following insulating materials (see Figure 3.4):
(I1= 16 mm, /^0.048WV(InK)
d2 = 140 mm, I2 = 0.033 W/(m K)
The temperatures are Tw = 30 0 C, TWi = 2 0 C . Calculate the heat loss per unit area of
the wall.
Solution
Area A=Im 2
(3.18)
(3.19)
(3.20)
(3.21)
(3.22)
The following example [2] illustrates the calculation of heat transfer through a tube as
shown in Figure 3.5.