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Determining the optimal policy 147<br />

Determining the optimal policy<br />

It can be seen that our decision tree consists of a set of policies. A policy<br />

is a plan of action stating which option is to be chosen at each decision<br />

node that might be reached under that policy. For example, one policy<br />

would be: choose the electrical design; if it fails, modify the design.<br />

Another policy would be: choose the electrical design; if it fails, abandon<br />

the project.<br />

We will now show how the decision tree can be used to identify<br />

the optimal policy. For simplicity, we will assume that the engineer<br />

considers that monetary return is the only attribute which is relevant<br />

to the decision, and we will also assume that, because the company is<br />

involved in a large number of projects, it is neutral to the risk involved<br />

in this development and therefore the expected monetary value (EMV)<br />

criterion is appropriate. Considerations of the timing of the cash flows<br />

and the relative preference for receiving cash flows at different points in<br />

time will also be excluded from our analysis (this issue is dealt with in<br />

Chapter 7).<br />

The technique for determining the optimal policy in a decision tree<br />

is known as the rollback method. To apply this method, we analyze<br />

the tree from right to left by considering the later decisions first. The<br />

process is illustrated in Figure 6.3. Thus if the company chose the<br />

electrical design and it failed (i.e. if the decision node labeled with an A<br />

was reached), what would be the best course of action? Modifying the<br />

design would lead to an expected return of (0.3 × $6 m) + (0.7 ×−$7 m),<br />

which equals −$3.1 m. Since this is worse than the −$3 m payoff that<br />

would be achieved if the design was abandoned, abandoning the design<br />

would be the best course of action. Two bars are therefore placed<br />

over the inferior branch and the ‘winning’ payoff is moved back to<br />

the decision node where it is now treated as a payoff for the ‘failure’<br />

branch. This means that the expected payoff of the electrical design is<br />

(0.75 × $10 m) + (0.25 ×−$3 m), which equals $6.75 m.<br />

The same analysis is applied to the section of the tree that represents<br />

the gas-powered design. It can be seen that if this design fails the best<br />

option is to modify it. Hence the expected payoff of the gas design is<br />

$11.24 m. This exceeds the expected payoff of the electrical design and<br />

the $0 payoff of not proceeding with the development. Two bars are<br />

therefore placed over the branches representing these options and the<br />

$11.24 m is moved back to the initial decision node. The optimum policy<br />

is therefore to develop the gas-powered design and, if it fails, to modify<br />

the design.

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