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Building Design and Construction Handbook - Merritt - Ventech!

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5.126 SECTION FIVE<br />

72M 72M<br />

ƒn�1 � ƒn �� (5.180)<br />

Ah Ah<br />

where ƒ is the stress in psi, M the moment in ft-lb from Step 4, A � plate crosssectional<br />

area <strong>and</strong> tension is taken as positive, compression as negative.<br />

Step 6. Apply a shear to adjoining edges to equalize the stresses there. Compute<br />

the adjusted stresses by converging approximations, similar to moment distribution.<br />

To do this, distribute the unbalanced stress at each edge in proportion to the reciprocals<br />

of the areas of the plates, <strong>and</strong> use a carry-over factor of � 1 ⁄2 to distribute<br />

the tress to a far edge. Edge 0, being a free edge, requires no distribution of the<br />

stress there. Edge 3, because of symmetry, may be treated the same, <strong>and</strong> distribution<br />

need be carried out only in the left half of the structure.<br />

Step 7. Compute the midspan edge deflections. In general, the vertical component<br />

� can be computed from<br />

where E � modulus of elasticity, psi<br />

k � tan � n � tan � , as in Step 3<br />

n�1<br />

� �<br />

E 15 ƒn�1 � ƒn ƒn � ƒn�1<br />

�n � � (5.181)<br />

2 L k a a<br />

n n n�1<br />

The factor E/L 2 is retained for convenience; it is eliminated by dividing the simultaneous<br />

angle equations by it. For a vertical plate, the vertical deflection is<br />

given by<br />

E 15(ƒn�1 � ƒ) n<br />

�n � (5.182)<br />

2 L hn Step 8. Compute the midspan angle change � P at each edge. This can be determined<br />

from<br />

E �n�1 � �n �n � �n�1<br />

�P �� � (5.183)<br />

2 L a a<br />

n n�1<br />

Step 9. To correct the edge rotations with a symmetrical loading, apply an unknown<br />

moment of �100m n sin (�x/L), in-lb (positive when clockwise) to plate n<br />

at edge n <strong>and</strong> �1000m n sin (�x/L) to its counterpart, plate n� at edge n�. Also,<br />

apply �1000m n sin (�x/L) to plate (n � 1) at edge n <strong>and</strong> �1000m n sin (�x/L)<br />

sine function is assumed to make the loading vary longitudinally in approximately<br />

the same manner as the deflections.) At midspan, the absolute value of these moments<br />

is 1000m n.<br />

The 12-in-wide transverse strip at midspan, hinged at the supports, will then be<br />

subjected at the supports to moments of 1000m n. Compute the rotations thus caused<br />

in the slabs from

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