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Building Design and Construction Handbook - Merritt - Ventech!

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STRUCTURAL THEORY 5.115<br />

k1 0 ... 0<br />

� �<br />

0 k 2 ... 0<br />

k � (5.162)<br />

.. .. ... ..<br />

0 0 ... kn Step 5. Develop a matrix b 0 that will transform the displacements � of the nodes<br />

of the structure into the displacement vector � while maintaining geometric compatibility:<br />

� � b � (5.163)<br />

0<br />

b 0 is a matrix of influence coefficients. The jth column of b 0 contains the element<br />

nodal displacements when the node where � j occurs is given a unit displacement<br />

in the direction of � j, <strong>and</strong> no other nodes are displaced.<br />

Step 6. Compute the stiffness matrix K for the whole structure from<br />

T K � bkb 0 0<br />

(5.164)<br />

T where b0 � transpose of b0 � matrix b0 with rows <strong>and</strong> columns interchanged<br />

T<br />

This equation may be derived as follows: From energy relationship, P � bS. 0<br />

Substitution of k� for S [Eq. (5.161)] <strong>and</strong> then substitution of b0� for � [Eq.<br />

T<br />

(5.163)] yields P � bkb 0 0�. Comparison of this with Eq. (5.103a), P � k� leads<br />

to Eq. (5.164).<br />

Step 7. With the stiffness matrix K now known, solve the simultaneous equations<br />

�1 � � K P (5.165)<br />

for the nodal displacements �. With these determined, calculate the member forces<br />

from<br />

S � kb0� (5.166)<br />

(N. M. Baran, ‘‘Finite Element Analysis on Microcomputers,’’ <strong>and</strong> H. Kardesluncer<br />

<strong>and</strong> D. H. Norris, ‘‘Finite Element H<strong>and</strong>book,’’ McGraw-Hill Publishing<br />

Company, New York; K. Bathe, ‘‘Finite Element Procedures in Engineering Analysis,’’<br />

T. R. Hughes, ‘‘The Finite Element Method,’’ W. Weaver, Jr., <strong>and</strong> P. R.<br />

Johnston, ‘‘Structural Dynamics by Finite Elements,’’ <strong>and</strong> H. T. Y. Yang, ‘‘Finite<br />

Element Structural Analysis,’’ Prentice-Hall, Englewood Cliffs, N.J.)<br />

5.14 STRESSES IN ARCHES<br />

An arch is a curved beam, the radius of curvature of which is very large relative<br />

to the depth of the section. It differs from a straight beam in that: (1) loads induce<br />

both bending <strong>and</strong> direct compressive stresses in an arch; (2) arch reactions have<br />

horizontal components even though loads are all vertical; <strong>and</strong> (3) deflections have<br />

horizontal as well as vertical components (see also Arts. 5.6.1 to 5.6.4). Names of<br />

arch parts are given in Fig. 5.93.

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