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Building Design and Construction Handbook - Merritt - Ventech!

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5.22 SECTION FIVE<br />

5.2.5 Poisson’s Ratio<br />

Within the elastic limit, when a material is subjected to axial loads, it deforms not<br />

only longitudinally but also laterally. Under tension, the cross section of a member<br />

decreases, <strong>and</strong> under compression, it increases. The ratio of the unit lateral strain<br />

to the unit longitudinal strain is called Poisson’s ratio.<br />

For many materials, this ratio can be taken equal to 0.25. For structural steel, it<br />

is usually assumed to be 0.3.<br />

Assume, for example, that a steel hanger with an area of 2 in 2 carries a 40-kip<br />

(40,000-lb) load. The unit stress is 40,000/2, or 20,000 psi. The unit tensile strain,<br />

taking the modulus of elasticity of the steel as 30,000,000 psi, is 20,000/<br />

30,000,000, or 0.00067 in/in. With Poisson’s ratio as 0.3, the unit lateral strain is<br />

�0.3 � 0.00067, or a shortening of 0.00020 in/in.<br />

5.2.6 Thermal Stresses<br />

When the temperature of a body changes, its dimensions also change. Forces are<br />

required to prevent such dimensional changes, <strong>and</strong> stresses are set up in the body<br />

by these forces.<br />

If � is the coefficient of expansion of the material <strong>and</strong> T the change in temperature,<br />

the unit strain in a bar restrained by external forces from exp<strong>and</strong>ing or contracting<br />

is<br />

According to Hooke’s law, the stress ƒ in the bar is<br />

where E � modulus of elasticity.<br />

5.2.7 Strain Energy<br />

� � �T (5.26)<br />

ƒ � E�T (5.27)<br />

When a bar is stressed, energy is stored in it. If a bar supporting a load P undergoes<br />

a deformation e the energy stored in it is<br />

1 U � ⁄2Pe (5.28)<br />

This equation assumes the load was applied gradually <strong>and</strong> the bar is not stressed<br />

beyond the proportional limit. It represents the area under the load-deformation<br />

curve up to the load P. Applying Eqs. (5.20) <strong>and</strong> (5.21) to Eq. (5.28) gives another<br />

useful equation for energy:<br />

where ƒ � unit stress<br />

E � modulus of elasticity of the material<br />

A � cross-sectional area<br />

L � length of the bar<br />

2 ƒ<br />

U � AL (5.29)<br />

2E

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