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Math 411: Honours Complex Variables - University of Alberta

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Chapter 12<br />

The Residue Theorem and<br />

Applications<br />

Definition. Let z0 ∈ C, let r > 0, and let f: Br(z0)\{z0} → C be holomorphic with<br />

Laurent series representation<br />

∞�<br />

f(z) = an(z −z0) n<br />

n=−∞<br />

for z ∈ Br(z0) \ {z0}. Then a−1 is called the residue <strong>of</strong> f at z0 and denoted by<br />

res(f,z0).<br />

Remarks. 1. By Theorem 9.3, we have<br />

for any ρ ∈ (0,r).<br />

res(f,z0) = 1<br />

2πi<br />

�<br />

∂Bρ(z0)<br />

f(ζ)dζ<br />

2. If f has a removable singularity at z0, then res(f,z0) = 0.<br />

3. Suppose that f has a simple pole at z0, i.e.<br />

∞�<br />

f(z) = an(z −z0) n<br />

with a−1 �= 0, then<br />

n=−1<br />

res(f,z0) = lim(z<br />

−z0)f(z).<br />

z→z0<br />

4. Suppose that f(z) = �∞ n=−kan(z −z0) n has a pole <strong>of</strong> order k at z0. On letting<br />

g(z) = (z−z0) kf(z), we see that res(f,z0) is the coefficient in the Taylor series<br />

<strong>of</strong>g(z) = �∞ n=−kan(z−z0) n+k = �∞ n=0an−k(z−z0) n corresponding to n = k−1:<br />

res(f,z0) = g(k−1) (z0)<br />

(k −1)! =<br />

1 d<br />

(k −1)!<br />

k−1<br />

dzk−1 �<br />

(z −z0) k f(z) �<br />

z=z0 .<br />

72

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