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Math 411: Honours Complex Variables - University of Alberta

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44 CHAPTER 6. CONVERGENCE OF HOLOMORPHIC FUNCTIONS<br />

Pro<strong>of</strong>. If γ : [a,b] → C is a curve (and thus continuous) then {γ} = γ([a,b]) is<br />

compact. Hence, Lemma 6.1 applies.<br />

Theorem 6.2 (Weierstraß Theorem). Let D ⊂ C be open, let f1,f2,... : D → C<br />

converges to f : D → C compactly. Then f is<br />

be holomorphic such that (fn) ∞ n=1<br />

holomorphic, and (f (k)<br />

n ) ∞ n=1 converges compactly to f (k) for each k ∈ N.<br />

Pro<strong>of</strong>. By Theorem 6.1, f is continuous.<br />

�<br />

To see that f is holomorphic, let ∆ ⊂ D be a triangle. By Goursat’s Lemma,<br />

∂∆fn(ζ)dζ = 0 holds for all n ∈ N. From Lemma 6.2, we conclude that<br />

� �<br />

f(ζ)dζ = lim fn(ζ)dζ = 0,<br />

n→∞<br />

∂∆<br />

i.e. f satisfies the Morera condition and thus is holomorphic.<br />

Let z0 ∈ D, and let 0 < r < R be such that Br[z0] ⊂ BR(z0) ⊂ BR[z0] ⊂ D. For<br />

any z ∈ Br(z0), we have<br />

|f ′ n (z)−f′ (z)| = 1<br />

2π<br />

Let ǫ > 0, and choose N ∈ N such that<br />

∂∆<br />

��<br />

�<br />

�<br />

fn(ζ)−f(ζ)<br />

�<br />

∂BR(z0) (ζ −z) 2<br />

�<br />

�<br />

dζ�<br />

�<br />

≤ 1<br />

2π ℓ(∂BR(z0))<br />

�<br />

�<br />

sup �<br />

fn(ζ)−f(ζ)<br />

� (ζ −z) 2<br />

�<br />

�<br />

�<br />

�<br />

≤<br />

ζ∈∂BR(z0)<br />

R<br />

(R−r) 2<br />

sup |fn(ζ)−f(ζ)|.<br />

ζ∈∂BR(z0)<br />

|fn(ζ)−f(ζ)|< ǫ (R−r)2<br />

R<br />

for all n ≥ N and ζ ∈ ∂BR(z0). Then it follows from the above estimates that<br />

|f ′ n (z)−f′ (z)|≤ ǫforall n ≥ N andz ∈ Br(z0). Consequently, (f ′ n |Br(z0)) ∞ n=1 converges<br />

to f ′ |Br(z0) uniformly on Br(z0). As z0 ∈ D is arbitrary, this means that (f ′ n) ∞ n=1<br />

converges to f locally uniformly, i.e. compactly, on D.<br />

For higher derivatives, the claim now follows by induction.<br />

Lemma 6.3. Let z0 ∈ C, let r > 0, and let z ∈ Br(z0). Then<br />

1<br />

ζ −z =<br />

∞�<br />

n=0<br />

converges absolutely and uniformly on ∂Br(z0).<br />

1 n<br />

(ζ −z0) n+1(z −z0)

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