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Math 411: Honours Complex Variables - University of Alberta

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26 CHAPTER 4. COMPLEX LINE INTEGRALS<br />

Then f is locally constant, but not constant.<br />

(i) =⇒ (iii): Let z ∈ D, and set<br />

U := {w ∈ D : ∃ a piecewise smooth curve γ: [a,b] → D with γ(a) = z, γ(b) = w}.<br />

Obviously, U �= ∅ (because z ∈ U).<br />

We claim that U is open. To see this, let w0 ∈ U, so that there exists a piecewise<br />

smooth curve γ: [a,b] → D with γ(a) = z and γ(b) = w0. Choose ǫ > 0 such that<br />

Bǫ(w0) ⊂ D. For w ∈ Bǫ(w0), we know that [w0,w] is a curve in Bǫ(w0) ⊂ D with<br />

initial point w0 and endpoint w. Consequently, γ ⊕ [w0,w] is a piecewise smooth<br />

curve in D with initial point z and endpoint w. It follows that w ∈ U, and since<br />

w ∈ Bǫ(w0) was arbitrary, we have Bǫ(w0) ⊂ U. This proves the openness <strong>of</strong> U.<br />

Next, we claim that D \ U is also open. To see this, let w0 ∈ D \ U, and let<br />

ǫ > 0 be so small that Bǫ(w0) ⊂ D. Assume towards a contradiction that there exists<br />

w ∈ Bǫ(w0)∩U. Let γ: [a,b] → D be a piecewise smooth curve with γ(a) = z and<br />

γ(b) = w. Then γ⊕[w,w0] is a piecewise smooth curve in D with initial point z and<br />

endpoint w0, so that w0 ∈ U. This contradicts the choice <strong>of</strong> w0 ∈ D \U. It follows<br />

that Bǫ(w0)∩U = ∅, i.e. Bǫ(w0) ⊂ D \U.<br />

Since U and D \U are both open with U ∪(D \U) = D and U ∩(D \U) = ∅,<br />

the connectedness <strong>of</strong> D yields that D\U = ∅, i.e. D = U.<br />

Lemma 4.1. Suppose D ⊂ C is an open connected set (a region) and f : D → C is<br />

continuous. Let z0 ∈ D. For each z ∈ D, let γz : [a,b] → D be a piecewise smooth<br />

curve in D such that γz(a) = z0 and γz(b) = z. Consider the function<br />

�<br />

F: D → C, z ↦→ f(ζ)dζ.<br />

For each z, let δ > 0 such that Bδ(z) ⊂ D. If the condition<br />

�<br />

F(w)−F(z) = f(ζ)dζ<br />

γz<br />

[z,w]<br />

holds for each z and all w ∈ Bδ(z), then F is an antiderivative for f.<br />

Pro<strong>of</strong>. Let z ∈ D. Given ǫ > 0, choose δ > 0 small enough such that Bδ(z) ⊂ D and<br />

For all w ∈ Bδ(z), we find<br />

� �<br />

�<br />

�<br />

F(w)−F(z) �<br />

� −f(z) �<br />

w −z � =<br />

|ζ −z|< δ ⇒ |f(ζ)−f(z)|< ǫ.<br />

=<br />

��<br />

1 �<br />

�<br />

|w−z| �<br />

��<br />

1 �<br />

�<br />

|w−z| �<br />

[z,w]<br />

[z,w]<br />

� �<br />

�<br />

f − f(z) �<br />

�<br />

[z,w]<br />

�<br />

�<br />

(f −f(z)) �<br />

�<br />

≤ |w−z|<br />

|w−z| sup{|f(ζ)−f(z)|: ζ ∈ {[z,w]}}<br />

= sup{|f(ζ)−f(z)|: ζ ∈ {[z,w]}} < ǫ.

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