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Math 411: Honours Complex Variables - University of Alberta

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z0 ∈ D, the germ <strong>of</strong> f at z0—denoted by 〈f〉z0—is the collection <strong>of</strong> all function<br />

elements (E,g) such that z0 ∈ E and there is a neighbourhood U ⊂ D∩E <strong>of</strong> z0 such<br />

that f(z) = g(z) for all z ∈ U.<br />

Definition. Let γ: [0,1] → C be a path, and suppose that, for each t ∈ [0,1], there<br />

is a function element (Dt,ft) such that:<br />

(a) γ(t) ∈ Dt;<br />

(b) there exists δ > 0 such that, whenever s ∈ [0,1] is such that |s − t|< δ, then<br />

γ(s) ∈ Dt and 〈fs〉γ(s) = 〈ft〉γ(s).<br />

Then we call {(Dt,ft) : t ∈ [0,1]} an analytic continuation along γ and say that<br />

(D1,f1) is obtained by analytic continuation <strong>of</strong> (D0,f0) along γ.<br />

Remark. Since γ is continuous and Dt is open for each t ∈ Dt, it is clear that there<br />

exists δ > 0 such that γ(s) ∈ Dt for all s ∈ [0,1] such that |s − t|< δ. What is<br />

important about part (b) <strong>of</strong> the definition is that 〈fs〉γ(s) = 〈ft〉γ(s), i.e. there is a<br />

neighbourhood Us ⊂ Ds ∩Dt <strong>of</strong> γ(s) such that fs(z) = ft(z) for z ∈ Us.<br />

γ(0)<br />

D0<br />

γ<br />

Theorem 15.1 (Monodromy Theorem). Let γ : [0,1] → C be a path, and let<br />

{(Dt,ft) : t ∈ [0,1]} and {(Et,gt) : t ∈ [0,1]} be analytic continuations along γ<br />

such that 〈f0〉γ(0) = 〈g0〉γ(0). Then we have 〈f1〉γ(1) = 〈g1〉γ(1).<br />

D1<br />

γ(1)<br />

105

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