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Draft BCPhysics11-4 Edvantage Interactive.pdf - BC Science ...

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Sample Problem 4.2.1 — Multiple Forces Acting on a Body<br />

A 45.0 N block is being pushed along a floor, where the coefficient of kinetic friction is 0.333. If a force of 25.0 N is<br />

applied, at what rate will the block accelerate? The mass of the block is 4.60 kg.<br />

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Figure 4.2.1 Forces acting on block<br />

What to think about<br />

1. Find the force of friction.<br />

2. Find the unbalanced force.<br />

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3. Find the acceleration.<br />

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How to Do It<br />

F f = µF n = µF g = (0.333) × (45.0 N) = 15.0 N<br />

unbalanced force = applied force – friction force<br />

F = 25.0 N – 15.0 N = 10.0 N<br />

a = F =<br />

10.0 N<br />

m 4.60 kg<br />

= 2.17 m/s2<br />

© <strong>Edvantage</strong> <strong>Interactive</strong> 2011 ISBN 978-0-9864778-3-6 Chapter 4 Newton’s Laws of Motion — DRAFT 171

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