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Rudarski radovi br 4 2011 - Institut za rudarstvo i metalurgiju Bor

Rudarski radovi br 4 2011 - Institut za rudarstvo i metalurgiju Bor

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Rz1 = t1<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz1 = α + 2;4−α<<strong>br</strong> />

Rz2 = Rz1+ t2<<strong>br</strong> />

[ ]<<strong>br</strong> />

t 2 = 2 α + 5;9 − 2α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz2 = α + 2+ 2α + 5;4− α + 9−2α [ ]<<strong>br</strong> />

Rz2 = 3α + 7;13−3α Rz3 = Rz2+ t3<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz3 = 3 α + 7 + 6α+ 24;13 − 3α+ 35−5α [ ]<<strong>br</strong> />

Rz3 = 9α + 31;48−8α Rz4 = Rz2+ t4<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz4 = 3 α + 7;13− 3α + 2α + 14;18 −2α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz4 = 5α + 21;31−5α Rz5 = Rz2+ t5<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz5 = 3 α + 7;13− 3α + α + 3;5 −α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz5 = 4α + 10;18−4α Rz6 = Rz2+ t6<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz6 = 3 α + 7;13− 3α + 3α + 7;12 −2α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz6 = 6 α + 14;25−5α R z1 = t1<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz1 = α + 2;4−α<<strong>br</strong> />

Rz2 = Rz1+ t2<<strong>br</strong> />

[ ]<<strong>br</strong> />

t2= 2 α + 5;9−2α [ ]<<strong>br</strong> />

Rz2 = α + 2+ 2α + 5;4− α + 9− 2α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz2 = 3α + 7;13−3α Rz3 = Rz2+ t3<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz3 = 3 α + 7 + 6α + 24;13− 3α + 35 −5α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz3 = 9α + 31;48−8α Rz4 = Rz2+ t4<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz4 = 3 α + 7;13 − 3α + 2α + 14;18 −2α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz4 = 5α + 21;31−5α Rz5 = Rz2+ t5<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz5 = 3 α + 7;13− 3α + α + 3;5−α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz5 = 4α + 10;18−4α Rz6 = Rz2+ t6<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz6 = 3 α + 7;13 − 3α + 3α + 7;12 −2α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz6 = 6 α + 14;25−5α Rz7 = Rz5+ t7<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz7 = 4 α + 10;18− 4α + 3α + 9;14−2α [ ]<<strong>br</strong> />

Rz7 = 7 α + 19;32−6α Rz8 = Rz5+ t8<<strong>br</strong> />

[ ] [ ]<<strong>br</strong> />

Rz8 = 4 α + 10;18− 4α + α + 1;3−α<<strong>br</strong> />

[ ]<<strong>br</strong> />

Rz8 = 5 α + 11;21−5α ⎡ ⎤<<strong>br</strong> />

Rz9 = max⎢Rz5+ t9; Rz6+ t9⎥<<strong>br</strong> />

⎢ ⎥<<strong>br</strong> />

⎣ ⎦<<strong>br</strong> />

Ovde primenjujemo postupak <strong>za</strong> poređenje<<strong>br</strong> />

fuzzy <strong>br</strong>ojeva, odnosno nalazimo<<strong>br</strong> />

najveću vrednost fuzzy <strong>br</strong>ojeva:<<strong>br</strong> />

Rz5+ t9= [ 4 α + 10;18− 4α]<<strong>br</strong> />

+<<strong>br</strong> />

[ 2α+ 13;17− 2α] = [ 6 α + 23;35−6α] Rz6+ t9= [ 6 α + 14;25− 5α]<<strong>br</strong> />

+<<strong>br</strong> />

[ 2α + 13;17 − 2α] = [ 8 α + 27;42 −7α]<<strong>br</strong> />

23 + 2 ⋅ 29 + 35<<strong>br</strong> />

RRz ( 5+ t9)<<strong>br</strong> />

= = 29,0<<strong>br</strong> />

4<<strong>br</strong> />

27 + 2 ⋅ 35 + 42<<strong>br</strong> />

RRz ( 6+ t9)<<strong>br</strong> />

= = 34,75<<strong>br</strong> />

4<<strong>br</strong> />

RRz ( 6+ t9) f RRz ( 6+ t9)<<strong>br</strong> />

Iz <strong>za</strong>dnje relacije sledi da je rani<<strong>br</strong> />

<strong>za</strong>vršetak <strong>za</strong> aktivnost 9 sledeći fuzzy<<strong>br</strong> />

Rz9 = 8 α + 27;42− 7α<<strong>br</strong> />

<strong>br</strong>oj: [ ]<<strong>br</strong> />

Broj 4,<strong>2011</strong>. 154<<strong>br</strong> />

RUDARSKI RADOVI

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