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Web skærmformat. - Aarhus Universitet

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IX. Opgaver – 2. Januar 2003 568<br />

Det følger, at<br />

= 1 1<br />

−<br />

3! 5! x2 − ...<br />

x − sin x<br />

lim<br />

x→0 x3 f(x) f(0)<br />

= lim =<br />

cos x x→0 cos x cos 0<br />

= 1<br />

6<br />

2.33. Angiv potensrække ☞ Matematik Alfa 1, Januar 2003<br />

Opgave 6 - figur<br />

Grafen for<br />

y =<br />

y<br />

1<br />

0 1<br />

x − sinx<br />

x 3 cos x<br />

x

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