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Web skærmformat. - Aarhus Universitet

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I. Differentiation – 3. Tangentplan 56<br />

til koordinatkurverne<br />

på grafen Γf .<br />

x ↦→ (x,y0,f(x,y0)), y ↦→ (x0,y,f(x0,y))<br />

3.7. Ligning for tangentplan ☞ [S] 11.4 Tangent planes and linear approx.<br />

2 Sætning<br />

Antag at f har kontinuerte partielle afledede fx,fy i en lille cirkelskive om (x0,y0). Tangentplanen<br />

for grafen i et punkt (x0,y0,z0), z0 = f(x0,y0) har ligning<br />

Bevis<br />

Indsættes<br />

z − z0 = fx(x0,y0)(x − x0) + fy(x0,y0)(y − y0)<br />

(x,y,z) = (x0,y0,z0) + (1,0,fx(x0,y0))<br />

= (x0 + 1,y0,z0 + fx(x0,y0))<br />

er ligningen opfyldt. Ligeså for den anden tangentvektor.<br />

3.8. Find tangentplan ☞ [S] 11.4 Tangent planes and linear . . .<br />

Eksempel 1<br />

Find ligningen for tangentplanen til<br />

z = 2x 2 + y 2<br />

i punktet (1,1,3).<br />

Løsning

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