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Web skærmformat. - Aarhus Universitet

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IX. Opgaver – 1. August 2002 546<br />

fuldstændig løsning<br />

y(x) = Ce A(x) + B(x)e A(x)<br />

= Ce −2x + ( 1<br />

2 x2 + 3<br />

2 e2x )e −2x<br />

= Ce −2x + 1<br />

2 x2 e −2x + 3<br />

2<br />

1.37. Løs differentialligning ☞ Matematik Alfa 1, August 2002<br />

Opgave 7 - retningsfelt<br />

y<br />

1<br />

0 1<br />

x

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