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Web skærmformat. - Aarhus Universitet

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V. Matricer – 3. Lineære ligninger 408<br />

2x1 − 2x2 − 4x3 − 6x4 = −16<br />

x2 + 2x3 + 6x4 = 4<br />

− 3x4 = 6<br />

3.12. Afslut bagfra ☞ [LA] 6 Løsningsteknik<br />

Eksempel’ - fortsat<br />

Heraf<br />

2x1 − 2x2 − 4x3 − 6x4 = −16<br />

x2 + 2x3 + 6x4 = 4<br />

− 3x4 = 6<br />

x4 = −2<br />

x2 = 4 − 2x3 − 6x4 = 16 − 2x3<br />

x1 = −8 + x2 + 2x3 + 3x4 = 2<br />

3.13. En fri tre bundne ☞ [LA] 6 Løsningsteknik<br />

Eksempel’ - fortsat<br />

Løsning<br />

x4 = −2<br />

x2 = 16 − 2x3<br />

x1 = 2

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