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Web skærmformat. - Aarhus Universitet

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V. Matricer – 2. Lineære afbildninger 397<br />

Den fuldstændige løsning er<br />

⎛ ⎞<br />

⎝<br />

hvor x3 kan vælges frit.<br />

x1<br />

x2<br />

x3<br />

⎠ =<br />

=<br />

⎛ ⎞ ⎛ ⎞<br />

x2 + 2x3 − 14 2<br />

⎝ −2x3 + 16 ⎠ = ⎝−2x3<br />

+ 16⎠<br />

x3<br />

x3<br />

⎛ ⎞<br />

2<br />

⎛<br />

0<br />

⎞ ⎛ ⎞<br />

2<br />

⎛ ⎞<br />

0<br />

⎝16⎠<br />

+ ⎝−2x3⎠<br />

= ⎝16⎠<br />

+ x3 ⎝−2⎠<br />

0<br />

0 1<br />

x3<br />

2.23. 1 ligning 3 ubkendte ☞ [LA] 5 Lineære ligningssystemer<br />

Eksempel 1’<br />

x1 + x2 + x3 = 1<br />

(1) Vælg x3 = x2 = 0 og løs x1 = 1<br />

(2) Det giver partikulær løsning<br />

(x1,x2,x3) = (1,0,0)<br />

2.24. 1 ligning 3 ubkendte ☞ [LA] 5 Lineære ligningssystemer<br />

Eksempel 1’ - fortsat

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