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Web skærmformat. - Aarhus Universitet

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II. Integration – 4. Koordinatskift 245<br />

Integralet er<br />

<br />

R<br />

x 2 π/2<br />

y dA =<br />

0<br />

2<br />

r<br />

0<br />

3 cos 2 (θ)sin(θ)rdr dθ<br />

4.34. Opgave<br />

Opgave 1 - fortsat<br />

☞ Matematik Alfa 1, August 2002<br />

<br />

x 2 π/2 2<br />

y dA = r 3 cos 2 (θ)sin(θ)rdr dθ<br />

R<br />

0<br />

π/2<br />

=<br />

0<br />

0<br />

<br />

1<br />

5 r5 cos 2 r=2 θ sin θ<br />

r=0<br />

π/2<br />

32<br />

=<br />

0 5 cos2 θ sinθ dθ<br />

<br />

= − 32<br />

15 cos3 π/2 θ<br />

= 32<br />

15<br />

4.35. Opgave ☞ Matematik Alfa 1, August 2002<br />

Opgave 1 - ny figur<br />

0<br />

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