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II. Integration – 3. Generelle områder 210 D = {(x,y)|c ≤ y ≤ d,h1(y) ≤ x ≤ h2(y)} 3.14. Type II ☞ [S] 12.3 Double integrals over general regions Type II integral For f givet på 4 D = {(x,y)|c ≤ y ≤ d,h1(y) ≤ x ≤ h2(y)} er integralet et itereret integral 5 D d h2(y) f(x,y)dA = f(x,y)dx dy c 3.15. Type II ☞ [S] 12.3 Double integrals over general regions Eksempel 2 Givet funktionen f(x,y) = x 2 + y 2 på Type II mængden h1(y) D = {(x,y)|0 ≤ y ≤ 4, 1 2 y ≤ x ≤ √ y}
II. Integration – 3. Generelle områder 211 Dobbelt integralet beregnes itereret f(x,y)dA = D 4 0 √ y 1 2 y (x 2 + y 2 )dx dy 3.16. Type II ☞ [S] 12.3 Double integrals over general regions Eksempel 2 - figur y 4 x = 1 2 y x = √ y D = {(x,y)|0 ≤ y ≤ 4, 1 2 y ≤ x ≤ √ y} 2 x
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CALCULUS "SLIDES" TIL CALCULUS 1 +
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3. Generelle områder 201 4. Koordi
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Forord "Slides" til forelæsningern
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I. Differentiation - 1. Kontinuitet
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V. Matricer - 4. Determinanter = (
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Litteratur • Arnold, Ordinary dif
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0-række/søjle, 423 n-te afsnitssu
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Identitetsmatricen, 383 Identitetsm
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