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II. Integration – 2. Itereret integral 188 2.10. Fortsat ☞ [S] 12.2 Iterated integrals Eksempel 1 - fortsat Itereret integral 3 2 0 1 A(x) = 3 2 x2 3 x 2 3 y dydx = 0 2 x2 dx = 3 3 3 x 2 3 = 3 3 2 3 3 = 27 2 2.11. Fortsat avet om ☞ [S] 12.2 Iterated integrals Eksempel 1 - fortsat R = [0,3] × [1,2], f(x,y) = x 2 y Partial integral A(y) = 3 0 x 2 y dx 0
II. Integration – 2. Itereret integral 189 3 x = 3 y x=3 x=0 y − 0 3 = 9y = 33 2.12. Sluttelig ens ☞ [S] 12.2 Iterated integrals Eksempel 1 - fortsat Itereret integral 2 3 1 0 A(y) = 9y x 2 y dxdy = 2 1 2 y = 9 2 = 9( 22 2 = 27 2 9y dy 2 1 − 12 2 )
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CALCULUS "SLIDES" TIL CALCULUS 1 +
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3. Generelle områder 201 4. Koordi
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Forord "Slides" til forelæsningern
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I. Differentiation - 1. Kontinuitet
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II. Integration - 4. Koordinatskift
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1. Grafiske/numeriske metoder IV Di
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V. Matricer - 4. Determinanter 419
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V. Matricer - 4. Determinanter = (
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1. Egenvektorer VI Egenvektorer og
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Litteratur • Arnold, Ordinary dif
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0-række/søjle, 423 n-te afsnitssu
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Identitetsmatricen, 383 Identitetsm
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