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I. Differentiation – 7. Lagrangemetoden 162 Løsning De partielle afledede er Det kritiske punkt (a,b) = ( 1 3 hx = 10x + 4y − 4,hy = 4x + 4y − 2 , 1 6 ) giver minimums punkt/værdi (a,b,c) = (1 3 , 1 6 1 1 , 6 ), f(a,b,c) = 6 .
1. Dobbelt integral II Integration 1.1. Oversigt ☞ [S] 5.2, 5.4, 12.1 Nøgleord og begreber ✌ Bestemt integral ✌ Areal ✌ Riemann summer ✌ Volumen ✌ Dobbelt integral ✌ Test dobbelt integral ✌ Riemann dobbeltsummer ✌ Nyttige regneregler for integral 163
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CALCULUS "SLIDES" TIL CALCULUS 1 +
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3. Generelle områder 201 4. Koordi
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Forord "Slides" til forelæsningern
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I. Differentiation - 1. Kontinuitet
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II. Integration - 3. Generelle omr
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1. Grafiske/numeriske metoder IV Di
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1. Vektorer og matricer V Matricer
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V. Matricer - 4. Determinanter 419
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V. Matricer - 4. Determinanter = (
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1. Egenvektorer VI Egenvektorer og
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Litteratur • Arnold, Ordinary dif
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0-række/søjle, 423 n-te afsnitssu
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Identitetsmatricen, 383 Identitetsm
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