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Web skærmformat. - Aarhus Universitet

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I. Differentiation – 6. Maksimum/minimum 137<br />

f har kritisk punkt<br />

∇f(x,y) = (2x − 2y, −2x + 2) = 0 ⇔<br />

(x,y) = (1,1)<br />

6.41. Ekstremumspunkter ☞ [S] 11.7 Maximum and minimum values<br />

Eksempel 7 - figur<br />

x<br />

3<br />

(3,2)<br />

z<br />

2<br />

y

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