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Web skærmformat. - Aarhus Universitet

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I. Differentiation – 6. Maksimum/minimum 122<br />

har kritisk punkt<br />

∇f(x,y) = (−2x,2y) = 0 ⇔ (x,y) = (0,0)<br />

f(x,0) < 0, f(0,y) > 0, (x,y) = 0<br />

viser, at (0,0) ikke er et lokalt ekstremum, altså er (0,0) et saddelpunkt.<br />

6.16. Ekstremumspunkt ☞ [S] 11.7 Maximum and minimum values<br />

Eksempel 2 - figur<br />

z<br />

x<br />

Saddelpunkt i (0,0)<br />

6.17. 2. ordens kriterium ☞ [S] 11.7 Maximum and minimum values<br />

y

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