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Web skærmformat. - Aarhus Universitet

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I. Differentiation – 5. Gradient 101<br />

Duf(x,y) = (2xy 3 ,3x 2 y 2 − 4) ·<br />

1<br />

√ 29 (2,5)<br />

= 1<br />

√ 29 (4xy 3 + 15x 2 y 2 − 20)<br />

5.23. Retningsafledt ☞ [S] 11.6 Directional derivatives and the . . .<br />

Eksempel 4 - fortsat<br />

I retning u = 1<br />

√ 29 (2,5) er<br />

I punktet (x,y) = (2, −1) fås<br />

Duf(x,y) = (2xy 3 ,3x 2 y 2 − 4) ·<br />

Duf(2, −1) = (−4,8) ·<br />

= 32<br />

√ 29<br />

1<br />

√ 29 (2,5)<br />

1<br />

√ 29 (2,5)<br />

5.24. Mange variable ☞ [S] 11.6 Directional derivatives and the . . .<br />

Bemærkning

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