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A4-format til udskrift. - Aarhus Universitet

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80 II. INTEGRATION<br />

1.26. Midtpunkter <strong>til</strong> beregning ☞ [S] 12.1 Double integrals over rectangles<br />

Eksempel 2 - igen<br />

R = [−1,1] × [−2,2], f(x,y) = 1 − x 2<br />

m = n = 2 og brug midtpunkter ¯x1 = −1 2 , ¯y1 = −1, ¯y2 = 1, ∆A = 2.<br />

Den dobbelte Riemann sum giver<br />

√<br />

2π = 1 − x2dA ≈ 4 3<br />

R<br />

2 , ¯x2 = 1<br />

6.28 ≈ 6.93<br />

1.27. Regneregler hjælper ☞ [S] 12.1 Double integrals over rectangles<br />

Regneregler for dobbeltintegral<br />

7<br />

8<br />

<br />

Hvis f(x,y) ≥ g(x,y), så er<br />

<br />

9<br />

<br />

(f(x,y) + g(x,y))dA = f(x,y)dA + g(x,y)dA<br />

R<br />

R<br />

<br />

<br />

cf(x,y)dA = c f(x,y)dA<br />

R<br />

R<br />

R<br />

<br />

f(x,y)dA ≥<br />

R<br />

R<br />

g(x,y)dA<br />

1.28. Brug regneregler<br />

Opgave<br />

☞ [S] 12.1 Double integrals over rectangles<br />

Lad R = [0,1] × [0,1]. Afgør om<br />

<br />

xy dA ≥ x 2 y 2 dA<br />

Løsning<br />

For 0 ≤ x,y ≤ 1 er<br />

så uligheden er sand ifølge regneregel 9 .<br />

R<br />

R<br />

xy ≥ x 2 y 2<br />

1.29. Brug regneregler ☞ [S] 12.1 Double integrals over rectangles<br />

Opgave<br />

Lad R = [0,2] × [0,2]. Afgør om <br />

(x + y)dA ≤ 16<br />

R<br />

Løsning<br />

For 0 ≤ x,y ≤ 2 er x + y ≤ 4<br />

så ifølge regneregel 9<br />

<br />

R<br />

<br />

(x + y)dA ≤<br />

R<br />

4dA ≤ 16<br />

1.30. Test integral regneregler ☞ [S] 12.1 Double integrals over rectangles<br />

Test<br />

Lad f(x,y) = xy, R = [1,2] × [1,2]. For integralet V = <br />

xy dA gælder uligheder<br />

R<br />

(a) 1 ≤ V ≤ 4. (b) 4 < V . (c) V < 1.

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