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A4-format til udskrift. - Aarhus Universitet

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6. MAKSIMUM/MINIMUM 57<br />

6.26. Lokalt maksimum/minimum ☞ [S] 11.7 Maximum and minimum values<br />

Eksempel 3 - figur<br />

x<br />

z<br />

z = x 4 + y 4 − 4xy + 1<br />

6.27. Ekstremumspunkters type ☞ [S] 11.7 Maximum and minimum values<br />

Eksempel 3 - fortsat<br />

giver<br />

fx = 4x 3 − 4y, fy = 4y 3 − 4x<br />

fxx = 12x 2 , fxy = −4, fyy = 12y 2<br />

D = fxxfyy − f 2 xy = 144x 2 y 2 − 16<br />

1. D(0,0) = −16 < 0 ⇒ (0,0) saddelpunkt<br />

2. D(1,1) = 128 > 0, fxx(1,1) = 12 > 0 ⇒ (1,1) lokalt minimum<br />

3. D(−1, −1) = 128 > 0, fxx(−1, −1) = 12 > 0 ⇒ (−1, −1) lokalt minimum<br />

6.28. Populært skema ☞ [S] 11.7 Maximum and minimum values<br />

Eksempel 3 - fortsat<br />

Konklusions skema<br />

(a,b) f(a,b) fxx(a,b) D(a,b) Type<br />

(0,0) 1 0 −16 saddel<br />

(1,1) −1 12 128 minimum<br />

(−1, −1) −1 12 128 minimum<br />

6.29. Ekstremumspunkters type ☞ [S] 11.7 Maximum and minimum values<br />

Eksempel 4 f(x,y) = 10x 2 y − 5x 2 − 4y 2 − x 4 − 2y 4<br />

har kritiske punkter, hvor<br />

Foruden (x,y) = (0,0) fås, x = 0<br />

20xy − 10x − 4x 3 = 0, 10x 2 − 8y − 8y 3 = 0<br />

10y − 5 − 2x 2 = 0, 5x 2 − 4y − 4y 3 = 0 ⇔<br />

10y − 5 − 2x 2 = 0, 8y 3 − 42y + 25 = 0 ⇔<br />

y<br />

... ⇔<br />

(x,y) ≈ (0,0),(±2.64,1.90),(±0.86,0.65)

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