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A4-format til udskrift. - Aarhus Universitet

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22 I. DIFFERENTIATION<br />

∂2f (x,y) = fyy(x,y)<br />

∂y2 ∂2f (x,y) = fyx(x,y)<br />

∂x∂y<br />

∂2f (x,y) = fxy(x,y)<br />

∂y∂x<br />

2.19. Mere afledning ☞ [S] 11.3 Partial derivatives<br />

Eksempel 1, 6<br />

Afledede og højere afledede<br />

f = x 3 + x 2 y 3 − 2y 2<br />

fx = 3x 2 + 2xy 3 , fy = 3x 2 y 2 − 4y<br />

fxx = 6x + 2y 3 , fyy = 6x 2 y − 4<br />

fxy = 6xy 2 , fyx = 6xy 2<br />

2.20. Endnu en afledning ☞ [S] 11.3 Partial derivatives<br />

Eksempel 3<br />

f(x,y) = sin( x<br />

1 + y )<br />

Afledede og højere afledede<br />

fx = cos( x 1<br />

)<br />

1 + y 1 + y<br />

fxx = −sin( x<br />

1 + y )<br />

1<br />

(1 + y) 2<br />

fxy = −sin( x −x x −1<br />

) + cos( )<br />

1 + y (1 + y) 3 1 + y (1 + y) 2<br />

2.21. Endnu en afledning ☞ [S] 11.3 Partial derivatives<br />

Eksempel 3 - fortsat<br />

f(x,y) = sin( x<br />

1 + y )<br />

Afledede og højere afledede<br />

fy = cos( x −x<br />

)<br />

1 + y (1 + y) 2<br />

fyy = −sin( x<br />

1 + y )<br />

x2 x<br />

+ cos(<br />

(1 + y) 4 1 + y )<br />

2x<br />

(1 + y) 3<br />

fyx = −sin( x −x x −1<br />

) + cos( )<br />

1 + y (1 + y) 3 1 + y (1 + y) 2

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