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A4-format til udskrift. - Aarhus Universitet

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106 II. INTEGRATION<br />

Det er<br />

{(r,θ,z)| −π<br />

2<br />

≤ θ ≤ π<br />

2 ,0 ≤ r ≤ 2cos θ,0 ≤ z ≤ r2 }<br />

4.24. Stub ☞ [S] 12.4 Double integrals in polar coordinates<br />

Eksempel 3 - skitse (lav bedre selv!)<br />

z<br />

x<br />

{(r,θ,z)| −π<br />

2<br />

≤ θ ≤ π<br />

2 ,0 ≤ r ≤ 2cos θ,0 ≤ z ≤ r2 }<br />

4.25. Polær Type II, eksempel ☞ [S] 12.4 Double integrals in polar . . .<br />

Eksempel 3 - fortsat<br />

Volumenet er et integral af funktionen<br />

på området i polære koordinater<br />

D = {(r,θ)| −π<br />

2<br />

f(x,y) = x 2 + y 2<br />

Dobbelt integralet beregnes ved koordinatskift<br />

<br />

V =<br />

R<br />

π<br />

≤ θ ≤ ,0 ≤ r ≤ 2cos θ}<br />

2<br />

π/2<br />

f(x,y)dA =<br />

−π/2<br />

2 cos θ<br />

0<br />

y<br />

r 2 rdr dθ<br />

4.26. Polær Type II, eksempel ☞ [S] 12.4 Double integrals in polar . . .<br />

Eksempel 3 - fortsat<br />

π/2 2 cos θ<br />

V = r 2 rdr dθ<br />

−π/2<br />

π/2 4 r<br />

=<br />

−π/2 4 r=0<br />

π/2<br />

= 4cos 4 θ dθ<br />

= ...<br />

= 3π<br />

2<br />

−π/2<br />

0<br />

r=2 cos θ<br />

4.27. Kilen ☞ [S] 12.4 Double integrals in polar . . .<br />

Kile<br />

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