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A4-format til udskrift. - Aarhus Universitet

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Dobbelt integralet beregnes itereret<br />

<br />

f(x,y)dA =<br />

D<br />

3. GENERELLE OMRÅDER 95<br />

2 2x<br />

0 x2 (x 2 + y 2 )dy dx<br />

3.19. Type I ☞ [S] 12.3 Double integrals over general regions<br />

Eksempel 2 - figur<br />

y<br />

4<br />

y = 2x y = x 2<br />

D = {(x,y)|0 ≤ x ≤ 2,x 2 ≤ y ≤ 2x}<br />

3.20. Type I ☞ [S] 12.3 Double integrals over general regions<br />

Eksempel 2 - fortsat <br />

(x<br />

D<br />

2 + y 2 2 2x<br />

)dA =<br />

0 x2 (x 2 + y 2 )dy dx<br />

2 <br />

= x<br />

0<br />

2 y + 1<br />

3 y3<br />

y=2x y=x2 dx<br />

2<br />

= (x<br />

0<br />

2 (2x) + 1<br />

3 (2x)3 − x 2 (x 2 ) − 1<br />

2 =<br />

<br />

− 1<br />

21 x7 − 1<br />

5 x5 + 7<br />

6 x4<br />

= 216<br />

35<br />

2<br />

0<br />

x<br />

3 (x2 ) 3 )dx<br />

3.21. Type II ☞ [S] 12.3 Double integrals over general regions<br />

Eksempel 3<br />

Givet funktionen<br />

f(x,y) = xy<br />

på Type II mængden<br />

D = {(x,y)| − 2 ≤ y ≤ 4, 1<br />

2 y2 − 3 ≤ x ≤ y + 1}<br />

Dobbelt integralet beregnes itereret<br />

<br />

y+1<br />

D<br />

f(x,y)dA =<br />

4<br />

−2<br />

1<br />

2 y2 −3<br />

xy dx dy<br />

3.22. Type II ☞ [S] 12.3 Double integrals over general regions<br />

Eksempel 3 - figur

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