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A4-format til udskrift. - Aarhus Universitet

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f(x2i 2)<br />

x2i 2<br />

1. DOBBELT INTEGRAL 79<br />

x2i 1<br />

Simpson<br />

f(x2i)<br />

x2i<br />

f(x2i 1)<br />

1.23. Midtpunktsstrategi ☞ [S] 12.1 Double integrals over rectangles<br />

Midtpunktsreglen<br />

Som middelpunkt bruges midtpunkter<br />

Tilnærmer dobbeltintegralet<br />

<br />

R<br />

x ∗ ij = ¯xi = xi−1 + xi<br />

2<br />

y ∗ ij = ¯yj = yj−1 + yj<br />

2<br />

f(x,y)dA ≈<br />

m<br />

i=1 j=1<br />

n<br />

f(¯xi, ¯yj)∆A<br />

1.24. Midtpunkter <strong>til</strong> beregning ☞ [S] 12.1 Double integrals over rectangles<br />

Eksempel 3<br />

R = [0,2] × [1,2], f(x,y) = x − 3y 2<br />

m = n = 2 og brug midtpunkter.<br />

y<br />

1 2<br />

Midtpunkter ¯x1 = 1<br />

2 , ¯x2 = 3<br />

2 , ¯y1 = 5<br />

4 , ¯y2 = 7<br />

4<br />

2<br />

1<br />

1.25. Brug midtpunktet ☞ [S] 12.1 Double integrals over rectangles<br />

Eksempel 3 - fortsat<br />

Midtpunkter ¯x1 = 1<br />

2 , ¯x2 = 3<br />

2 , ¯y1 = 5<br />

4 , ¯y2 = 7<br />

4<br />

∆A = 1<br />

2<br />

Den dobbelte Riemann sum giver<br />

<br />

R<br />

(x − 3y 2 )dA<br />

≈ (f( 1<br />

2<br />

= − 95<br />

8<br />

, 5<br />

4<br />

) + f(1<br />

2<br />

, 7<br />

4<br />

x<br />

) + f(3<br />

2<br />

, 5<br />

4<br />

x<br />

7<br />

) + f(3 ,<br />

2 4 ))1<br />

2

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